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likoan [24]
3 years ago
9

What is a root of a quadratic equation?

Mathematics
1 answer:
Elodia [21]3 years ago
6 0
The root is the x-intercepts
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a gas station sells regular gas for $2.10 per gallon and premium gas for $2.90 a gallon. at the end of a business day 280 gallon
insens350 [35]

200 gallons of regular gas and 80 gallons of premium gas were sold.

Let the amount of regular gas sold be x gallons. So, the amount of premium gas sold will be (280 - x).

Now, forming the equation using the given information, to find the amount of each type of gallon.

Equation -

2.10x + 2.90(280 - x) = 652

Performing multiplication with values inside bracket in Left Hand Side

2.10x + 812 - 2.90x = 652

Rewriting the equation -

812 - 652 = 2.90x - 2.10x

Performing subtraction

160  = 0.8x

Rewriting the equation according to x

x = 160÷0.8

Performing division to find the value of x

x = 200

So, 200 gallons of regular gas was sold.

Amount of premium gas sold = 280 - 200

Performing subtraction

Amount of premium gas sold = 80 gallons

Hence, 200 gallons of regular gas and 80 gallons of premium gas was sold.

Learn more about problems on gas -

brainly.com/question/14746001

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4 0
1 year ago
Mini Sweets bake shop is running a special on cupcakes. For every 10 cupcakes purchased, 3 free cupcakes are added to the order.
Ierofanga [76]
She would get 9 free cupcakes
8 0
3 years ago
What is the value of x?<br><br> Please include steps on how to get to the answer. &lt;3
AlekseyPX
We have that 
<span>Bisector theorem--------------- >(LM)/(LN)=(OM)/(ON)
therefore
</span>(18)/(10)=(x)/(4)------------------ > x=7.2

 the answer is x=7.2
6 0
3 years ago
Please help right in <br>y=mx+b form
slavikrds [6]
Y=2/2x+0
hope this helps

ps~~u dont need that 0
4 0
3 years ago
Julien's parents want $64,000 at the end of 3 years. They put their money in an account that yields 10% per year compounded mont
Leto [7]

Answer: \$47,471

Step-by-step explanation:

Given

Julien's parents want $64,000 at the end of 3 years

The rate of interest is 10% annually

Suppose they invested P amount initially

So, compound interest, compounded monthly is

\Rightarrow A=P\left( 1+\frac{r}{n}\right)^{nt}\quad [\text{n=Numner of compounding periods}]\\\\\text{Insert the values}\\\Rightarrow 64,000=P\left( 1+\frac{0.10}{12}\right)^{12\times 3}\\\\\Rightarrow 64,000=P\left( 1+\frac{10}{12}\right)^{36}\\\\\Rightarrow P=\dfrac{64000}{1.3481}\\\\\Rightarrow P=\$\ 47,471.37\approx \$ 47,471

7 0
2 years ago
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