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Cerrena [4.2K]
3 years ago
8

Area codes are the first three digits of a 10-digit telephone number. The first digit of an area code cannot be 0 or 1.

Mathematics
1 answer:
astra-53 [7]3 years ago
7 0

Answer:A

Step-by-step explanation:because the numbers can be allowed to be repeated

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Evaluate the function for <br> f (2) = x^3 - 2<br><br> A.4 <br> B.6 <br> C.8<br> D.10
ElenaW [278]

Answer:

A. 4

Step-by-step explanation:

Hope this helps!

5 0
3 years ago
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Figure. <br> What are the pairs of congruent angles?
Anna35 [415]

∠QRS and ∠CDE are congruent.

∠RST and ∠DEB are congruent.

∠STQ and ∠EBC are congruent.

∠TQR and ∠BCD are congruent.


You can conclude the above angles are congruent because ∠R and ∠D has the same sign on their angle and so does ∠S and ∠E.

7 0
3 years ago
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Hannah has information about an object in circular orbit around Earth. MEarth = 6. 0 × 1024 kg G = 6. 67 × 10–11 StartFraction m
castortr0y [4]

In order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

<h3>What is the tangential speed of the object?</h3>

The tangential speed of an object is the linear component of the speed, which is moving in a circular path.

In terms of  the gravitation constant, the tangential speed can be given as,

v=\sqrt{\dfrac{Gm}{r}}

Here, {<em>G</em>} is the gravitation constant, (<em>m</em>) is the mass and (<em>r</em>) is the radius.

Hannah has information about an object in circular orbit around Earth.

The mass of the earth is.

m_E=6. 0 \times10^{24} kg

The value of gravitational constant is,

G=6. 67\times 10{-11}\rm Nm^2/kg^2

The radius of the earth is,

r_E=6. 0 \times 10^6 \rm m

Here, only the distance of the orbiting object to Earth is need to find the tangential speed of the object.

Hence, in order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

Learn more about the tangential speed here;

brainly.com/question/4933588

7 0
2 years ago
What is the slope of the line that passes through the points 0, 2 and 4, -1.
sesenic [268]

Answer:

Ithink that the answer will be ( -1/3 ) .

8 0
3 years ago
What time was it 2011 minutes after the beginning of January 1
PIT_PIT [208]
Okay! 

Notable things in the problem:
2011 <u>minutes</u> <u>AFTER</u> the beginning of January 1rst. 

12:00AM will be our starting time, because that's when January 1rst begins. 
It'll be a bit easier to work with if we convert the 2011 minutes into hours. 
So take 2011 minutes and divide it by 60 to get the number of hours. 

2011 / 60 = 33 hours and 31 minutes

You wouldn't be able to easily get the exact number of minutes from a calculator. You'll need to use long division. The remainder will be the number of minutes. If you want to check you can multiply the number of hours by 60 and add 31 to the product. If it doesn't equal 2011 minutes then something is amiss. 

12:00 AM 

Since we know this is a 24 hour clock we can subtract 24 from our number of hours. (Just remember that this is the next day) 

12:00 AM with 9 hours and 31 minutes left. 

9:31 AM a day later is our time!<u />
8 0
3 years ago
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