the standard equation of the circle having the given center and radius is 
.
Assuming width=diameter
diameter/2=radius
area=hpir^2
w=d=2
d/2=2/2=1=r
h=6
area=6pi1^2
area=6pi1
area=6pi
aprox pi=3.141592
area=18.85 cm³
{(-1,3),(-1,4),(-1,5),(-1,6)} is the set from the given question which is a set of ordered pairs representing a function.
<h3>What is ordered pair?</h3>
An ordered pair (a, b) in mathematics is a group of two things. The pair's order of objects matters because the ordered pair (a, b) differs from the ordered pair (b, a) unless a = b. (By contrast, an unordered pair of a and b equals an unordered pair of b and a.)
Ordered pairs are also known as 2-tuples, or sequences (or, in computer science, occasionally, lists) of length 2. Sometimes referred to as 2-dimensional vectors, ordered pairs of scalars. Technically speaking, this is a misuse of the term because an ordered pair need not be a component of a vector space. An ordered pair's entries may be other ordered pairs, allowing for the recursive definition of ordered n-tuples (ordered lists of n objects).
Learn more about ordered pairs
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Answer:
x=0
Step-by-step explanation:
2(x+4)- 5 = 3x+3
Distribute
2x+8-5 = 3x+3
Subtract x values
8-5 = x+3
3 = x+3
Final Subtraction
x = 0
Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
