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2 years ago

What is the vertex form of f(x)=2x2+ 6x -8

Mathematics

2 answers:

aev [14]2 years ago

7 0

Hopefully this helped!!

katrin2010 [14]2 years ago

3 0

This parabola has a minimum (since the coefficient of x^2 is positive). To find the vertex of a quadratic equation ax^2 + bx + c =0, you calculate (-b/a) or in our case (-6/4) = -3/2. This is the value of x. Now to find the value of y, you just plug x by its value (-3/2) & you'll find y =(-25/2) so the coordinate of the vertex are (-3/2 , -25/2).

Hope this is clear

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A local mechanic charges customers a flat fee of $60 before any work is done and a rate of $85 per hour of labor which equation

Alexus [3.1K]

Answer:

L=85H+60

Step-by-step explanation:

i know

5 0

3 years ago

Help ASAP!!<br>Using the graphed function above, find the following

Alenkinab [10]

Answer:

Maximum: 1, Minimum: -3, Midline y = -1, Amplitude = 4, Period = $\pi$ , Frequency $\displaystyle =\frac{1}{\pi}$ , equation : $f(x)=-4cos(2x)+1$

Step-by-step explanation:

<u>Sinusoid Functions</u>

It refers to the oscillating functions like the sine or cosine which range from a minimum and maximum value periodically.

The graph shown can give us all the information we need to answer these questions:

Maximum: 1

Minimum: -3

The midline goes through the center value (mean) of the max and min values, i.e.

Equation of the midline:

$\displaystyle y=\frac{1-3}{2}=-1$

Amplitude is the difference between the maximum and minimum values

$A=1-(-3)=4$

The period is the time it takes to complete a cycle. We can see the minimum value is first reached at x=0 and next at $x=\pi$

Thus the period is

$T=\pi$

The frequency is the reciprocal of the period:

$\displaystyle f=\frac{1}{T}=\frac{1}{\pi}$

The angular frequency is

$\displaystyle w=2\pi f=\frac{2\pi }{\pi}=2$

The equation of the function is a negative cosine (since it starts at the minimum) or a shifted sine or cosine. We'll choose the negative cosine, knowing all the parameters:

$f(x)=-4cos(2x)+1$

5 0

3 years ago

Which method would you use to prove that the two triangles are congruent?

Alona [7]

Answer:- AAS postulate

Explanation:-

AAS postulate tells that if two angles and a non-included side of a triangle to equal to the two angles and a non-included side of another triangle then the two triangles are said to be congruent.

Given:- One angle and one side of a triangle is equal to the one angle and one side of the other triangle.

We see there is one more pair of equal angles as they are vertically opposite angles . [See the attachment]

⇒ there is a triangle where two angles and a non-included side of a triangle to equal to the two angles and a non-included side of another triangle then the two triangles are said to be congruent.

⇒ The triangles are congruent [ by ASA postulate]