Answer:
b. 144.8
Step-by-step explanation:
When calculating the moving average estimate of an observation , each of the observations are usually computed with the same weighted . In some cases, it is beneficial to assign different weight on the observations such that the observation closer to the time period being forecast, has higher weight. This is refer to as weighted moving average technique. The sum of the individual weight in a weighted moving average technique must equal to 1.
The three-period weighted moving average forecast for period 5 = 144*0.5 + 148 *0.3 + 142 *0.2 = 144.8
Answer:
∠1 = 72°
Step-by-step explanation:
Complementary angles sum to 90°, thus
∠1 + ∠2 = 90, substitute ∠1 = 4∠2 , thus
4∠2 + ∠2 = 90
5∠2 = 90 ( divide both sides by 5 )
∠2 = 18°
Hence ∠1 = 90 - 18 = 72°
X = large boxes and y = small boxes
x + y = 70.....x = 70 - y
60x + 65y = 4300
60(70 - y) + 65y = 4300
4200 - 60y + 65y = 4300
5y = 4300 - 4200
5y = 100
y = 100/5
y = 20 <=== the small boxes weigh 20 lbs
x + y = 70
x + 20 = 70
x = 70 - 20
x = 50 <== and the large boxes weigh 50 lbs
Answer:
A. 3a-2=54
Step-by-step explanation:
3 x her age - the 2 year will equal 54
The graph is stretch/shrunk by a factor of a. The Domain is h=
