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3 years ago

9282 divided by 433 with a remainder

Mathematics

1 answer:

Studentka2010 [4]3 years ago

7 0

Step-by-step explanation:

the explanation is pictured

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- If MML = (11x - 5), mJK = (4x + 26)° and mZMNL = (10x – 12), find mZMNL.

GenaCL600 [577]

Answer:

m∠ MNL = 78º

Step-by-step explanation:

Arcs meassures

mML = (11x - 5)º

mJK = (4x + 26)°

Angle meassure

m∠MNL = (10 x – 12)º

______________________

angle measure = average of arcs

m∠MNL = (mML+ mJK)/2

Replacing

(10x – 12)º = ((11x - 5)º + (4x + 26)° )/ 2

10x -12 = (15x + 21 )/2

10x - 7.5x = 10.5 + 12

2.5x = 22.5

x= 9

m∠MNL = (10 x – 12)º

= 90 - 12

= 78º

3 0

3 years ago

What are the intercepts for x and y ? thanks in advance

SpyIntel [72]

Answer:

see explanation

Step-by-step explanation:

The x- intercept is the value of x where the line crosses the x- axis.

The x- intercept is (0.3, 0)

The y- intercept is the value of y where the line crosses the y- axis

The y- intercept is (0, 0.4)

3 0

2 years ago

Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )

DedPeter [7]

(a) First find the intersections of $y=e^{2x-x^2}$ and $y=2$ :

$2=e^{2x-x^2}\implies \ln2=2x-x^2\implies x=1\pm\sqrt{1-\ln2}$

So the area of $R$ is given by

$\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx$

If you're not familiar with the error function $\mathrm{erf}(x)$ , then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

(b) Find the intersections of the line $y=1$ with $y=e^{2x-x^2}$ .

$1=e^{2x-x^2}\implies 0=2x-x^2\implies x=0,x=2$

So the area of $S$ is given by

$\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx$
$\displaystyle=2\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\mathrm dx$

which is approximately 1.546.

(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve $y=e^{2x-x^2}$ and the line $y=1$ , or $e^{2x-x^2}-1$ . The area of any such circle is $\pi$ times the square of its radius. Since the curve intersects the axis of revolution at $x=0$ and $x=2$ , the volume would be given by

$\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx$

5 0

3 years ago

Please Evaluate 27 times ( 1/3) to the 3 power. A). 1 B). 3 C). 9 D). 27

topjm [15]

Answer:

you want to follow PEMDAS so you would multiply 27 by 1/3 to get 81.003, which you would round to 81, then you would multiply 8 to the third power and you would get 512.

Step-by-step explanation:

27(1/3)^3

81^3

512

7 0

2 years ago

How would u write three times a number x

Law Incorporation [45]

Can write 3x or 3(x) or 3•x

7 0

2 years ago

Read 2 more answers