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Zigmanuir [339]
3 years ago
6

convert 15/9 to a decimal round your answer to the nearest hundred.convert 15/9 to a decimal round your answer to the nearest hu

ndred ​
Mathematics
2 answers:
dalvyx [7]3 years ago
8 0

First, the whole part,

15/9=1 and 6/9

So the form will be 1.<something>

Next the decimal part,

6/9=2/3=0.6666...

So the number is 1.66666... but we need to round to the nearest hundredth.

If we write the number up until hundredth we would get,

1.66[66666...] but the next decimal is 6 which is more than 5 so we add 1 to the hundredth and get 1.67.

Hope this helps :)

motikmotik3 years ago
6 0

Answer:

1.67

Step-by-step explanation:

after the decimal we have the

tens

hundreths

thousanths

(usually math doesn't ask you to go farther than the thousanths place)

because 15/9 is 1.66666, you will go to the hundreths place and round that six. Six is one more than five so it gets rounded up. That changes the decimal to 1.67.  You do not change it to 1.7, because it asked you to round to the nearest hundred not the nearest tens

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3 years ago
At an airport, 79% of recent flights have arrived on time. A sample of 7flights is studied. a.Compute the mean of this probabili
xxTIMURxx [149]

Answer:

a. 5.53

b. 1.078

c. 0.126

d. 0.109

e. 0.549

f. 0.834

g.  0.451

Step-by-step explanation:

The percentage of the flights that arrive on time, P(x) = 79%

The number of flights in the sample, n = 7 flights

a. The mean of the probability distribution, μ = ∑x·P(x)

Therefore, we have; μₓ = n·p

μₓ = 7 × 79/100 = 5.53

b. The standard deviation, σₓ = √(n·p·(1 - p))

∴ σₓ = √(7 × 0.79 × (1 - 0.79)) ≈ 1.078

c. We have;

p = 0.79

q = 1 - p = 1 - 0.79 = 0.21

By binomial probability distribution formula, we have;

The probability of exactly four, P(Exactly 4) = ₇C₄·p⁴·q³

P(Exactly 4) = 35 × 0.79⁴×0.21³ ≈ 0.12625

d. The probability of less than 4 is given as follows;

P(Less than 4) = ₇C₀·p⁰·q⁷ + ₇C₁·p¹·q⁶ + ₇C₂·p²·q⁵ + ₇C₃·p³·q⁴

∴ P(Less than 4) = 1×0.79^0 * 0.21^7 + 7 * 0.79^1 × 0.21^6 + 21*0.79^2*0.29^5+ 85×0.79^3*0.21^4 ≈ 0.109

The probability of less than 4 is ≈ 0.109

e. The probability that more than 5 is given as follows;

P(More than 5) = ₇C₆·p⁶·q¹ + ₇C₇·p⁷·q⁰

7×0.79^6 * 0.21 + 1 * 0.79^7 × 0.21^0 ≈ 0.549

f. The probability that at least 5 of the flight were on time is given as follows;

P(At least 5) = ₇C₅·p⁵·q² + ₇C₆·p⁶·q¹ + ₇C₇·p⁷·q⁰

∴ P(At least 5) = 21×0.79^5 * 0.21^2 + 7×0.79^6 * 0.21 + 1 * 0.79^7 × 0.21^0 ≈ 0.834

g.  For the probability that no more than 5 of the flights were on time, e have;

P(At most 5) = 1 - P(More than 5)

∴ P(At most 5) = 1 - 0.549 ≈ 0.451.

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What is the work and answer to 16.8÷0.8
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Hi

16.8/0.8 = 168/8 = 21
    
     168 |__8__
    -16     21
     ------
      08
    - 08 
     ------
      00

Answer: 21

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