Pythagorean theorem
for a right triangle with legs legnth a and b and hytponuse c
a^2+b^2=c^2
the legnht of th eladder is the hypotnuse
the 3 feet is bottom leg
height is other leg
10=c
3=a
b=?
3^2+b^2=10^2
9+b^2=100
minus 9 both sides
b^2=91
sqrt both sides
b=√91
aprox
b=9.53939
answer is √91 feet or aprox 9.53939
Answer:
FG = 16
Step-by-step explanation:
we can state that ΔEFG ≅ ΔEHG due to the Angle-Angle-Side postulate
this means that FG = GH
we can use this equation to solve for 'x':
x + 11 = 3x + 1
11 = 2x + 1
10 = 2x
5 = x
FG = x + 11 or 5 + 11, which is 16
Answer:
(27 - P) / 3P = r
Step-by-step explanation:
A = P(1 + rt)
A = 27
27 = P(1 + 3r)
27 = P + 3Pr
27 - P = 3Pr
(27 - P) / 3P = r
