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o-na [289]
3 years ago
8

The problem C(x)=25x+50 represents the labor coat in dollars for quick cedar to build a deck where x is the number of hours of l

abor

Mathematics
1 answer:
AVprozaik [17]3 years ago
3 0

Answer: 18.6 or 93/5

Step-by-step explanation:

See attached picture

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Enos took out a 25-year loan for $135,000 at an APR of 6.0%, compounded monthly, and he is making monthly payments of $869.81. W
Alborosie
Present value = 135000
Monthly interest, i = 0.06/12 = 0.005
Monthly payment, A= 869.81

Future value of loan after 16 years
F=P(1+i)^n      [compound interest formula]
=135000(1+.005)^{16*12}
=351736.652

Future value of payments after 16 years
\frac{A((1+i)^n-1)}{i}
=\frac{869.81((1+0.005)^{16*12}-1)}{0.005}
=279287.456

Balance = future value of loan - future value of payments
=351736.652-279288.456
= $ 72448.20

Note: the exact monthly payment for a 25-year mortgage is
A=\frac{P(i*(1+i)^n)}{(1+i)^n-1}
=\frac{135000(0.005*(1+0.005)^{25*12}}{(1+0.005)^{25*12}-1}
=869.806892

Repeating the previous calculation with this "exact" monthly payment gives
Balance = 72448.197, very close to one of the choices.

So we conclude that the exact value obtained above differs from the answer choices is due to the precision (or lack of it) of the provided data.

The closest choice is therefore <span>$72,449.19</span>
6 0
3 years ago
Read 2 more answers
Help please !!!
slava [35]
C is the best answer choice
8 0
3 years ago
Which line is the graph of y = x?
satela [25.4K]

B in has the intersection with quadrant 1 and 3

5 0
3 years ago
Brad has 10,000 in the bank and saves $225 each month. Write an equation to compute how much money Brad has saved. Let y be the
Yuri [45]
The equation is
y = $10,000+ $225x


<em>$225 (6) + $10,000 = y</em>

<em>$1,350 + $10,000 = y</em>

<em>$11,350 = y</em>

He will have saved $11,350 dollars in six months.
5 0
3 years ago
What is the value of x in: 1/7x -6 =8 (11-3)
Lynna [10]
1/7x - 6 = 8(11-3)
1/7x - 6 = 8(8)
1/7x - 6 = 64
1/7x = 70
1/7 = 70x
1 = 490x
1/490 = x
6 0
3 years ago
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