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3 years ago

Solve 5 - 8 sin x = 5+2 sin x for 0° ≤ x ≤ 180° degrees

Mathematics

2 answers:

just olya [345]3 years ago

7 0

I think it’s 90 degrees
But idk

Arte-miy333 [17]3 years ago

6 0

Answer:

answer is 30

Step-by-step explanation:

you thought

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3 years ago

0.39 over 0.75 as a decimal

STatiana [176]

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3 years ago

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3(2x - 4) = 4(x + 1) X=__?

Doss [256]

Answer:

Step-by-step explanation:

SIMPLIFY

6X-12=4X+4

PUT LIKE TERMS TOGETHER

6X-4X=4+12

SIMPLIFY

2X=16

X=16/2

X=8

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

✌ -ZYLYNN JADE ARDENNE

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4 years ago

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Hi, help with question 18 please. thanks

Vadim26 [7]

Answer:

See Below.

Step-by-step explanation:

We are given the equation:

$\displaystyle y^2 = 1 + \sin x$

And we want to prove that:

$\displaystyle 2y\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right) ^2 + y^2 = 1$

Find the first derivative by taking the derivative of both sides with respect to x:

$\displaystyle 2y \frac{dy}{dx} = \cos x$

Divide both sides by 2y:

<h3> $\displaystyle \frac{dy}{dx} = \frac{\cos x}{2y}$ </h3>

Find the second derivative using the quotient rule:

$\displaystyle \begin{aligned} \frac{d^2y}{dx^2} &= \frac{(\cos x)'(2y) - (\cos x)(2y)'}{(2y)^2}\\ \\ &= \frac{-2y\sin x-2\cos x \dfrac{dy}{dx}}{4y^2} \\ \\ &= -\frac{y\sin x + \cos x\left(\dfrac{\cos x}{2y}\right)}{2y^2} \\ \\ &= -\frac{2y^2\sin x+\cos ^2 x}{4y^3}\end{aligned}$

Substitute:

$\displaystyle 2y\left(-\frac{2y^2\sin x+\cos ^2 x}{4y^3}\right) + 2\left(\frac{\cos x}{2y}\right)^2 +y^2 = 1$

Simplify:

$\displaystyle \frac{-2y^2\sin x-\cos ^2x}{2y^2} + \frac{\cos ^2 x}{2y^2} + y^2 = 1$

Combine fractions:

$\displaystyle \frac{\left(-2y^2\sin x -\cos^2 x\right)+\left(\cos ^2 x\right)}{2y^2} + y^2 = 1$

Simplify:

$\displaystyle \frac{-2y^2\sin x }{2y^2} + y^2 = 1$

Cancel:

$\displaystyle -\sin x + y^2 = 1$

Substitute:

$-\sin x + \left( 1 + \sin x\right) =1$

Simplify. Hence:

$1\stackrel{\checkmark}{=}1$

Q.E.D.

8 0

3 years ago

In step 2, how do you know that 5x? and -12x? are like terms? If you could please help me with 1,2,3 if not just 2

klemol [59]

First we need to define what a like term is:

Like term meaning:

Terms whose variables (such as x or y) with any exponents (such as the 2 in x2) are the same. Examples: 7x and 2x are like terms because they are both "x".

Answer (for question 1):
For step one, you would just have to expand the brackets. The number of times multiplication would be used is 3 times. If you are confused, I attached a diagram in my ‘side notes’ section.

Answer (for question 2):
-5x squared and -12x squared are like terms because they both end in x squared.

Answer (for question 3):
There are no more like-terms.

Hope this helps!
Please give Brainliest!

Side notes:

3 0

2 years ago