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Tamiku [17]
3 years ago
13

[Precalculus] Use trigonometric identities to express:

Mathematics
1 answer:
ehidna [41]3 years ago
4 0

Remark

<u>Two facts.</u>

1) Tan(x) = Sin(x) / Cos(x)

2) Csc(x) and Sin(x) are reciprocal relationships. When multiplied together, they equal 1.

Solution

So Csc(x) * tan(x) = csc(x) * sin(x) / cos(x) = 1/cos(x) = sec(x)

So far what we have is tan^2(x) + sec(x). We have to get rid of tan^2(x)

Use the identity of 1 + tan^2(x) = sec^2(x)

tan^2(x) = sec^2(x) - 1

sec^2(x) - 1 + sec(x)

a^2 + a - 1   <<<<<< Answer

B is the answer.


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Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th
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The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

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S = \{1,1,2,2,2,3\}

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P(1) = \frac{n(1)}{n(s)}

P(1) = \frac{2}{6}

P(1) = \frac{1}{3}

P(2) = \frac{n(2)}{n(s)}

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P(2) = \frac{1}{2}

P(3) = \frac{n(3)}{n(s)}

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P(Odd Number) is then calculated as:

P(Odd\ Number) =  P(1) + P(3)

P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}

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P(Odd\ Number) = \frac{2+1}{6}

P(Odd\ Number) = \frac{3}{6}

P(Odd\ Number) =  \frac{1}{2}

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

S = \{1,1,2,2,2,3,3\}

The probability of each is:

P(1) = \frac{n(1)}{n(s)}

P(1) = \frac{2}{7}

P(2) = \frac{n(2)}{n(s)}

P(2) = \frac{3}{7}

P(3) = \frac{n(3)}{n(s)}

P(3) = \frac{1}{7}

P(Odd\ Number) = P(1) + P(3)

P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}

Take LCM

P(Odd\ Number) = \frac{2+1}{7}

P(Odd\ Number) = \frac{3}{7}

Comparing P(Odd Number) before and after

P(Odd\ Number) =  \frac{1}{2} --- Before

P(Odd\ Number) = \frac{3}{7} --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

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George finished 10 of 25 math problems.what percent of the problems did george finish
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Answer:

40%

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So 10/25=0.4

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