5 1/8+5/6+5/12=6.375 what is 6.375 as a fraction? A 6 3/4. B.6 3/8. C6 3/12. D 6 3/24 please help

1 answer:

3 0

B. 6 3/8
How do we get this? Simple:
6.375--->We already know that 6 will be the whole number in the mixed fraction.

We then move on to represent the decimal part as the fraction. 375 will be the numerator. The denominator depends on how many decimal places we have (3 in this case, since there are 3 numbers after the period--375). Each decimal place represents a 10 (or a 0 after the 1). So we get that our denominator will be a 1000.

We get the following fraction
6 375/1000

We simplify. Let's start by dividing numerator and denominator by 5:
6 75/200

Let's divide by 5 again:
6 15/40

Let's divide by 5 again:
6 3/8

Or we could have divide by 125 from the get go and get the same results.

You might be interested in

Sandra, who is paid time-and-a-half for hours worked in excess of 40 hours, had gross weekly wages of $ 608 or 56 hours worke

vodomira [7]

Time-and-a-half doesn't make enough sense to answer the question. If you fix it, or comment below the correction I will gladly help.

4 0

4 years ago

PLEASE HELP <br><br> Which relation is a function?!

tia_tia [17]

The answer is the third one aka C.

There must not be two points on the same y-axis because that doesn't make a function but a relation instead.

C. doesn't have 2 points on same y-axis and therefore the third picture is the relation that's a function.

4 0

3 years ago

Solve the compound inequality, then correctly fill in the blanks below.<br> -3 2-5 <2<br> I

lesantik [10]

Answer:

hold my picolr

Step-by-step explanation:

7 0

3 years ago

Battery packs in electric go-carts need to last a fairly long time. The run-times (time until it needs to be recharged) of the b

pav-90 [236]

Answer:

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 2, \sigma = 0.33$