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2 years ago

9

Can someone please help me with this!?

1 answer:

vichka [17]2 years ago

4 0

Answer:

$2(x - 5)$

Step-by-step explanation:

$2x - 10$

$\frac{2x}{2} - \frac{10}{2}$

$2(x - 5)$

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Jacob is 5 5/6 feet tall. Linda is 5 1/4 feet tall. How much taller is Jacob?

SCORPION-xisa [38]

This problem boils down to 5/6 - 1/4

To subtract these fractions you need a common denominator.

I'll use 12

The first fraction becomes 10/12 and the second fraction becomes 3/12

10/12-3/12 = 7/12

So Jacob is 7/12 of a foot taller than Linda.

Also note than since 12 inches = 1 foot, you could say Jacob is 7 inches taller than Linda

6 0

3 years ago

Read 2 more answers

Help me please<br><br> please show WORK and just don’t put answer to get brainlest

Tamiku [17]

Answer:

11.25

Step-by-step explanation:

4.5 / 2 = 2.25 cups/ cup rice

2.25 x 2 cups of rice = 4.5 cups of water.

5 x 2.25 = 11.25

4 0

3 years ago

What set of reflections would carry trapezoid ABCD onto itself? (1 point) Trapezoid ABCD is shown. A is at negative 5, 1. B is a

amid [387]

Answer:

y=x, x axis, y=x, y axis

Step-by-step explanation:

If a point A(x, y) is reflected along the y = x line, the new coordinates would be A'(y, x)

If a point A(x, y) is reflected across the x axis, the new coordinates would be A'(x, -y)

If a point A(x, y) is reflected along the y axis, the new coordinates would be A'(-x, y)

Firstly reflect Trapezoid ABCD along the y = x line to give:

A (-5, 1) ⇒ A'(1, -5). B (-4, 3) ⇒ B'(3, -4). C (-2, 3) ⇒C'(3, -2). D (-1, 1) ⇒ D'(1, -1)

Secondly reflect along the x axis to give:

A'(1, -5)⇒ A"(1,5). B'(3, -4)⇒ B"(3,4), C'(3, -2)⇒C"(3, 2), D'(1, -1) ⇒ D"(1, 1)

Thirdly reflect along the y = x line to give:

A"(1,5) ⇒ A"'(5, 1). B"(3,4) ⇒ B"'(4, 3). C"(3, 2) ⇒ C"'(2, 3). D"(1, 1) ⇒ D"'(1, 1)

Lastly reflect along the y axis to give:

A"'(5, 1) ⇒ A""(-5, 1), B"'(4, 3) ⇒ B""(-4, 3), C"'(2, 3) ⇒ C""(-2, 3), D"'(1, 1) ⇒ D""(-1.1)

6 0

3 years ago

Write an equation for the perpendicular line to the line whose equation is 4y-5x=20 that contains the point (-2,-3)

yuradex [85]

Answer:

4x + 5y = - 23

Step-by-step explanation:

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 4y - 5x = 20 into this form

add 5x to both sides

4y = 5x + 20 ( divide all terms by 4 )

y = $\frac{5}{4}$ x + 5 ← in slope-intercept form

with slope m = $\frac{5}{4}$

given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ , hence

$m_{perpendicular}$ = - 1 / $\frac{5}{4}$ = - $\frac{4}{5}$

y = - $\frac{4}{5}$ x + c ← is the partial equation

to find c substitute (- 2, - 3) into the partial equation

- 3 = $\frac{8}{5}$ + c ⇒ c = - $\frac{23}{5}$

y = - $\frac{4}{5}$ x - $\frac{23}{5}$ ← in slope-intercept form

multiply all terms by 5

5y = - 4x - 23 ( add 4x to both sides )

4x + 5y = - 23 ← in standard form

7 0

3 years ago

HEY I NEE HELP WILL GIVE BRAINLIST

Crazy boy [7]

Answer:

I can help as welllll

Step-by-step explanation:

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3 years ago