All categories

3 years ago

The motion of a guitar string as it moves would be an example of:

Physics

2 answers:

sattari [20]3 years ago

6 0

Answer:

C Vibrational motion

Explanation:

vibrational motion is when the sound is endured from going side to side

Salsk061 [2.6K]3 years ago

3 0

Answer:

C) Vibrational motion

Explanation:

As we know that the guitar string will vibrate about its mean position in such a way that it will oscillate to and fro.

Due to this to and fro motion of the string of the guitar the air molecules will start oscillating and this disturbance of air will produce sound in the air column attached with the guitar string

So here the motion of guitar string is to and fro motion about the mean position of the string

this type of to and fro motion about the mean position is known as Vibrational Motion.

You might be interested in

At 25 mph, it will take you about how many feet to stop your car?

sp2606 [1]

It will take approximately 8 - 10 feet.

7 0

3 years ago

A shark travels with an average velocity of 12 m/s s. How long (time) would it take the shark to swim 42 m at that velocity

liq [111]

Answer:

t=3.5 seconds

Explanation:

Moving at Constant Speed

Let's suppose and object travels in a constant direction and covers the same distances x at the same time t, we say it has a constant speed. It can be computed as:

$\displaystyle v=\frac{x}{t}$

The time taken to go through the distance x is computed by

$\displaystyle t=\frac{x}{v}$

Our shark moves at v=12 m/s and we need to compute the time it takes to swim x=42 m, so we have

$\displaystyle t=\frac{42}{12}$

$\boxed{t=3.5\ seconds}$

It takes the shark 3.5 seconds to swim 42 m

5 0

4 years ago

Physical data is often used in the court system. In fact, police officers use radar to determine your speed when you are driving

Mashcka [7]

The driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.

The given parameters:

Speed of the driver observed by the stationary police officer, Vo = 44.7 m/s
Speed of the driver, V = 26.8 m/s.
Speed limit = 60 mph

The speed limit of the driver in meter per second is calculated as follows;

$= 60 \ \times \frac{miles}{hour} \times \frac{1609.34 \ m}{1 \ mile} \times \frac{1 \ hr}{3600 \ s}\\\\= 26.82 \ m/s$

From the speed limit, it is obvious that the driver's speed is within the limit. Thus, we can conclude that the driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.

Learn more about relative velocity here: brainly.com/question/17228388

6 0

2 years ago

Physics B 2020 Unit 3 Test

weqwewe [10]

Answer:

When a charge is in motion in a magnetic field, the charge experiences a force of magnitude

$F=qvB sin \theta$

where here:

For the proton in this problem:

$q=1.602\cdot 10^{-19}C$ is the charge of the proton

v = 300 m/s is the speed of the proton

B = 19 T is the magnetic field

$\theta=65^{\circ}$ is the angle between the directions of v and B

So the force is

$F=(1.602\cdot 10^{-19})(300)(19)(sin 65^{\circ})=8.28\cdot 10^{-16} N$

The magnetic field produced by a bar magnet has field lines going from the North pole towards the South Pole.

The density of the field lines at any point tells how strong is the magnetic field at that point.

If we observe the field lines around a magnet, we observe that:

- The density of field lines is higher near the Poles

- The density of field lines is lower far from the Poles

Therefore, this means that the magnetic field of a magnet is stronger near the North and South Pole.

The right hand rule gives the direction of the force experienced by a charged particle moving in a magnetic field.

It can be applied as follows:

- Direction of index finger = direction of motion of the charge

- Direction of middle finger = direction of magnetic field

- Direction of thumb = direction of the force (for a negative charge, the direction must be reversed)

In this problem:

- Direction of motion = to the right (index finger)

- Direction of field = downward (middle finger)

- Direction of force = into the screen (thumb)

The radius of a particle moving in a magnetic field is given by:

$r=\frac{mv}{qB}$

where here we have:

$m=6.64\cdot 10^{-22} kg$ is the mass of the alpha particle

$v=2155 m/s$ is the speed of the alpha particle

$q=2\cdot 1.602\cdot 10^{-19}=3.204\cdot 10^{-19}C$ is the charge of the alpha particle

B = 12.2 T is the strength of the magnetic field

Substituting, we find:

$r=\frac{(6.64\cdot 10^{-22})(2155)}{(3.204\cdot 10^{-19})(12.2)}=0.366 m$

The cyclotron frequency of a charged particle in circular motion in a magnetic field is:

$f=\frac{qB}{2\pi m}$

where here:

$q=1.602\cdot 10^{-19}C$ is the charge of the electron

B = 0.0045 T is the strength of the magnetic field

$m=9.31\cdot 10^{-31} kg$ is the mass of the electron

Substituting, we find:

$f=\frac{(1.602\cdot 10^{-19})(0.0045)}{2\pi (9.31\cdot 10^{-31})}=1.23\cdot 10^8 Hz$

When a charged particle moves in a magnetic field, its path has a helical shape, because it is the composition of two motions:

1- A uniform motion in a certain direction

2- A circular motion in the direction perpendicular to the magnetic field

The second motion is due to the presence of the magnetic force. However, we know that the direction of the magnetic force depends on the sign of the charge: when the sign of the charge is changed, the direction of the force is reversed.

Therefore in this case, when the particle gains the opposite charge, the circular motion 2) changes sign, so the path will remains helical, but it reverses direction.

The electromotive force induced in a conducting loop due to electromagnetic induction is given by Faraday-Newmann-Lenz:

$\epsilon=-\frac{N\Delta \Phi}{\Delta t}$

where

N is the number of turns in the loop

$\Delta \Phi$ is the change in magnetic flux through the loop

$\Delta t$ is the time elapsed

From the formula, we see that the emf is induced in the loop (and so, a current is also induced) only if $\Delta \Phi \neq 0$ , which means only if there is a change in magnetic flux through the loop: this occurs if the magnetic field is changing, or if the area of the loop is changing, or if the angle between the loop and the field is changing.

The flux is calculated as

$\Phi = BA sin \theta$

where

B = 5.5 T is the strength of the magnetic field

A is the area of the coil

$\theta=18^{\circ}$ is the angle between the direction of the field and the plane of the loop

Here the loop is rectangular with lenght 15 cm and width 8 cm, so the area is

$A=(0.15 m)(0.08 m)=0.012 m^2$

So the flux is

$\Phi = (5.5)(0.012)(sin 18^{\circ})=0.021 Wb$

See the last 7 answers in the attached document.

Download docx

docx

pdf

5 0

3 years ago

Consider a blimp that can be approximated as a 3-m diameter, 8-m long ellipsoid and is connected to the ground. On a windless da

Marta_Voda [28]

Step 1 of 6

Diameter of the blimp,

Length of the blimp,

Rope tension,

The velocity of the wind,

Step 2 of 6

The drag force acting on the blimp can be calculated using the formula given below,

(1)

Where, is the drag coefficient is the density of air.

A is the frontal area of the blimp.

V is the velocity of the wind.

Step 3 of 6

The frontal area of the parachute,

Here,

Substitute the value in the above equation.

The drag coefficient for the balloon is,

Step 4 of 6

From the table properties of air,

The density of air at 1atm pressure and is,

The velocity of air,

Step 5 of 6

Now, substitute all the known values in equation (1)

Step 6 of 6

Now, rope tension is the sum of rope tension due to the buoyancy effect and the force due to the wind blowing.

Learn more about the velocity at

brainly.com/question/4931057

#SPJ4

5 0

2 years ago