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melamori03 [73]
3 years ago
10

What does this circle graph tell you about water on Earth? (2 points)

Physics
1 answer:
vekshin13 years ago
8 0

Answer:

ocean covers 71 percent of the earth

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A 1-kg collar (located at point (2,2) from the origin) is pulled along a vertical, frictionless bar with a force of 10 N applied
faltersainse [42]

Answer:

The acceleration of the collar is 10 m/s²

Explanation:

Given;

mass of the collar, m = 1 kg

applied force on the bar, F = 10 N

The acceleration of the collar can be calculated by applying Newton's second law of motion;

F = ma

where;

F is the applied force

m is mass of the object

a is the acceleration

a = F / m

a = 10 / 1

a = 10 m/s²

Therefore, the acceleration of the collar is 10 m/s²

3 0
3 years ago
Which of the following is a unit of acceleration?
olasank [31]

{\tt{\red{\underline{\underline{\huge{Answer:}}}}}}

\longrightarrow The rate of change of velocity per unit time is called acceleration.

\longrightarrow Its SI unit is m/s².

\huge\boxed{\fcolorbox{blue}{red}{Thank you}}

7 0
3 years ago
How do very high density objects appear in an ultrasound?
evablogger [386]
<span>Density is entirely unrelated to an object's size. It is a property of a given</span>
7 0
3 years ago
Assume that a 15-kg ball moving at 8 m/s strikes a wall perpendicularly and rebounds elastically at the same speed. What is the
Aleks [24]
I think u should follow the formulae F=MA. So I think the answer is 120N
5 0
3 years ago
A fully loaded cart with a mass of 2200 kg starts from the top of a 12-meter hill on a roller coaster.
Salsk061 [2.6K]

Answer:

A. potential energy is 258720 Joule

Explanation:

A.Gravitational potential energy is: PE = m × g × h

velocity =  15.33 m/s when the car reaches the bottom of the hill.

where, m = mass

            g = acceleration due to gravity

            h = height from the bottom of hill.

The potential energy is : m×g×h

                                     =(2200×9.8×12)

                                     =258720 Joule

B. at the bottom of the hill, the potential energy is converted into kinetic energy so PE at top = KE at bottom

                    kinetic energy= \frac{1}{2}(m*v^{2})

where v = velocity

          m= mass

therefore,               v=\sqrt\frac{2*K.E}{m} {}

                         or,  v=\sqrt{\frac{2*258720}{2200} }

                         or,   v=15.33 m/s

7 0
3 years ago
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