Answer:
The acceleration of the collar is 10 m/s²
Explanation:
Given;
mass of the collar, m = 1 kg
applied force on the bar, F = 10 N
The acceleration of the collar can be calculated by applying Newton's second law of motion;
F = ma
where;
F is the applied force
m is mass of the object
a is the acceleration
a = F / m
a = 10 / 1
a = 10 m/s²
Therefore, the acceleration of the collar is 10 m/s²
 
        
             
        
        
        

 The rate of change of velocity per unit time is called acceleration.
 The rate of change of velocity per unit time is called acceleration.
 Its SI unit is m/s².
 Its SI unit is m/s².

 
        
             
        
        
        
<span>Density is entirely unrelated to an object's size. It is a property of a given</span>
        
             
        
        
        
I think u should follow the formulae F=MA. So I think the answer is 120N
        
             
        
        
        
Answer:
A. potential energy is 258720 Joule 
Explanation:
A.Gravitational potential energy is: PE = m × g × h 
velocity =  15.33 m/s when the car reaches the bottom of the hill. 
where, m = mass
             g = acceleration due to gravity
             h = height from the bottom of hill. 
The potential energy is : m×g×h
                                      =(2200×9.8×12) 
                                      =258720 Joule
B. at the bottom of the hill, the potential energy is converted into kinetic energy so PE at top = KE at bottom 
                     kinetic energy=  (
( )
)
where v = velocity
           m= mass 
therefore,               v=
                          or,  v=
                          or,   v=15.33 m/s