What does this circle graph tell you about water on Earth? (2 points)

How long does it take to move a mass of 0.85kg with an acceleration of 5.4m/s2 if it occured over 19m and 98w of power is produc

erik [133]

Answer:1 minute

Explanation:

3 0

4 years ago

Read 2 more answers

If you could cut the paper in half 20 times, would the paper be bigger or smaller than the following: 1 hair--------------------

mihalych1998 [28]

Answer:

Maybe???

Explanation:

but how big is the paper?

but I think even the paper is super big, the ending result will still be too small to observe …

7 0

3 years ago

James threw a ball vertically upward with a velocity of 41.67ms-1 and after 2 second David threw a ball vertically upward with a

Reptile [31]

Answer:

When have passed 3.9[s], since James threw the ball.

Explanation:

First, we analyze the ball thrown by James and we will find the final height and velocity by the time two seconds have passed.

We'll use the kinematics equations to find these two unknowns.

$y=y_{0} +v_{0} *t+\frac{1}{2} *g*t^{2} \\where:\\y= elevation [m]\\y_{0}=initial height [m]\\v_{0}= initial velocity [m/s] =41.67[m/s]\\t = time passed [s]\\g= gravity [m/s^2]=9.81[m/s^2]\\Now replacing:\\y=0+41.67 *(2)-\frac{1}{2} *(9.81)*(2)^{2} \\\\y=63.72[m]\\$

Note: The sign for the gravity is minus because it is acting against the movement.

Now we can find the velocity after 2 seconds.

$v_{f} =v_{o} +g*t\\replacing:\\v_{f} =41.67-(9.81)*(2)\\\\v_{f}=22.05[m/s]$

Note: The sign for the gravity is minus because it is acting against the movement.

Now we can take these values calculated as initial values, taking into account that two seconds have already passed. In this way, we can find the time, through the equations of kinematics.

$y=y_{o} +v_{o} *t-\frac{1}{2} *g*t^{2} \\y=63.72 +22.05 *t-\frac{1}{2} *(9.81)*t^{2} \\\\y=63.72 +22.05 *t-4.905*t^{2} \\$

As we can see the equation is based on Time (t).

Now we can establish with the conditions of the ball launched by David a new equation for y (elevation) in function of t, then we match these equations and find time t

$y=y_{o} +v_{o} *t+\frac{1}{2} *g*t^{2} \\where:\\v_{o} =55.56[m/s] = initial velocity\\y_{o} =0[m]\\now replacing\\63.72 +22.05 *t-(4.905)*t^{2} =0 +55.56 *t-(4.905)*t^{2} \\63.72 +22.05 *t =0 +55.56 *t\\63.72 = 33.51*t\\t=1.9[s]$

Then the time when both balls are going to be the same height will be when 2 [s] plus 1.9 [s] have passed after David throws the ball.

Time = 2 + 1.9 = 3.9[s]

4 0

3 years ago

Linear momentum is the product of mass and acceleration

tensa zangetsu [6.8K]

Answer:

This statement is false , linear momentum is the product of mass and velocity

5 0

3 years ago

Read 2 more answers

How is thermal energy being transferred between the water and the thermometer?

Goshia [24]

Answer:

When the thermometer is warmed, the liquid expands by more than the volume of the hollow space in which it is confined, and so some of it must move from the bulb into the capillary tube. It should be conduction and then convection/advection, not radiation. Radiation is usually the slowest heat transfer.

8 0

3 years ago