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Goryan [66]
4 years ago
15

Write the equation is logarithmic form

Mathematics
1 answer:
jasenka [17]4 years ago
4 0
We use the log rule logₐ b = x   ⇒   aˣ = b

Given (3)³ = 27

Following the rule, we can write (3)³ = 27 as

log₃ 27 = 3

Correct Answer: C
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Anyone know how to do this
svlad2 [7]

Answer:

The area of the rectangle on the left side is

9cm \:  \times 4cm = 36 {cm}^{2}

The area of the bottom rectangle is

6cm \times 2cm = 12 {cm}^{2}

The total area of the composite figure will be

36 {cm}^{2}  + 12 {cm}^{2}  = 48 {cm}^{2}

Step-by-step explanation:

The area of any given rectangle can be found by multiplying the length of that rectangle by its width. The rectangle on the left side has a length of 9cm but the width is unknown. To find the width, we subtract 6cm from the width of the bottom rectangle: 10cm. And that gives us 4cm.

Therefore, we can now calculate the area to be: length × width = 9cm × 4cm = 36cm²//

The area of the bottom rectangle can be found similarly by multiplying the length: 2cm by the width: 6cm of that rectangle. And the result gives us: 2cm × 6cm = 12cm²//

The total area of the composite figure is calculated by adding the results from the left and bottom rectangles together. And that gives us: 36cm² + 12cm² = 48cm²//

8 0
3 years ago
The gini ratio of income inequality ranges between: question 18 options:
hram777 [196]
The answer is d) 0 and 1.
8 0
4 years ago
What is 5r-3/2???????
Andrej [43]
3.5r.....................
8 0
3 years ago
The position of an object moving along a straight line for
NikAS [45]

Answer:

at 2/3 seconds

Step-by-step explanation:

S1(t) = t³ + 2

Average speed, dS1/dt = 3t²

S2(t) = t²

Average speed, dS2/dt = 2t

The distance between the objects is

dS1/dt - dS2/dt

= 3t² - 2t

The time the distance between the two object is at minimum is when the distance is 0

That is, when

3t² - 2t = 0

t(3t - 2) = 0

t = 0 or 3t - 2 = 0

t = 0 or t = 2/3

3 0
4 years ago
PLEASE HELP WILL MARK BRAINLIST!
storchak [24]
Every single one of those polynomials factors.  When factored, your expression looks like this: \frac{(3x-7)(x+3)}{x+3)(x-2)} * \frac{(2x+7)(x+9)}{(3x-7)(2x+7)}.  When you cancel the like factors out, what you're left with is this: \frac{1x+9}{1x-2}.  That means that b = 9, c = 1, and d = -2
7 0
3 years ago
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