Question

What is the equation of the axis of symmetry for the parabola y equals negative start fraction one over two end fraction left parenthesis x plus three right parenthesis squared minus five?x=-5x=-3x=-1/2x=3

Answer 1

For the equation,
y = 1/2(x+3)^2 -5
The vertice is (-3,-5). Therefore the axis of symmetry is X = -3.

Answer 2

Answer:

the equation of the axis of symmetry for the parabola is:

                               $x=-3$

Step-by-step explanation:

The equation of the parabola is given by:

             $y=-\dfrac{1}{2}(x+3)^2-5$

We know that for the general equation of the parabola of the type:

$y=a(x-h)^2+k$

The vertex of the parabola is at (h,k)

and the axis of symmetry of the parabola is :  x=h

Here after comparing the equation of parabola with the general equation of parabola we have:

$h=-3$

Hence, the axis of symmetry of the given parabola is:

                                 $x=-3$