Answer:
1.25+√3 or 2.9821 to the nearest ten thousandth.
Step-by-step explanation:
sin 60 = √3/2, tan 45 = 1 and cos^2 60 = (1/2)^2 = 1/4
So we get 2 *√3/2 + 1 + 1/4
= √3 + 1.25
Solution
Question 1:
- Use of the area of squares to explain the Pythagoras theorem is given below
- The 3 squares given above have dimensions: a, b, and c.
- The areas of the squares are given by:
- The Pythagoras theorem states that:
"The sum of the areas of the smaller squares add up to the area of the biggest square"
Thus, we have:
Question 2:
- We can apply the theorem as follows:
![\begin{gathered} 10^2+24^2=c^2 \\ 100+576=c^2 \\ 676=c^2 \\ \text{Take square root of both sides} \\ \\ c=\sqrt[]{676} \\ c=26 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2010%5E2%2B24%5E2%3Dc%5E2%20%5C%5C%20100%2B576%3Dc%5E2%20%5C%5C%20676%3Dc%5E2%20%5C%5C%20%5Ctext%7BTake%20square%20root%20of%20both%20sides%7D%20%5C%5C%20%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B676%7D%20%5C%5C%20c%3D26%20%5Cend%7Bgathered%7D)
Thus, the value of c is 26
Definition of eo-primes or relatively primes: Two numbers are said to be co-prime or relatively prime If their HCF IS 1 Hence to prove 847 and 2160 as co-prime numbers we will find their HCF and which should be 1
New steps to find HCF will be as under
2160 = 847 x 2+ 466
847 = 466 ×1 +381
466 = 381 x 1 + 85
381 =85 x 4+ 41
85 =41 x 2+3
41 =3 x 13+ 2
3 =2 x 1+1
2 =1 x 2+0
Therefore, the HCF=1 Hence, the numbers are co-primes (relatively prime).
Perimeter of square = 4 x l
so ATC 4 x l = 240
= 240/40= l
so 60 = l
the answer is 60 inches.
As an integer and a raitonal number as well as a real number.
