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grin007 [14]
3 years ago
12

The product of 5 and a number x is 1/4. what is the value of x?

Mathematics
2 answers:
mars1129 [50]3 years ago
6 0

I had this same question nd the answer was


B. 1/20

solniwko [45]3 years ago
4 0
The mathematical expression is
5x = 1/4
Divide:
x = (1/4)/5 = (1/4)*5 = 5/4 (ANSWER)
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Which second degree polynomial function f(x) has a lead coefficient of 3 and roots 4 and 1?
Stella [2.4K]

Answer:

f(x) = 3x² - 15x + 12

Step-by-step explanation:

Given f(x) has roots x = a and x = b, then

(x - a) and (x - b) are the factors

f(x) is then the product of the factors

f(x) = a(x - a)(x - b) ← where a is a multiplier

Given roots are x = 4 and x = 1, then

(x - 4) and (x - 1) are the factors

With a = 3, then

f(x) = 3(x - 4)(x - 1) ← expand factors using FOIL

     = 3(x² - 5x + 4) ← distribute

     = 3x² - 15x + 12

7 0
4 years ago
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Tickets to a play are priced as follows:
Aneli [31]
£72 plus £18 equals £90 and 10% makes it £81.00 and with the 2% it’s £82.62
3 0
4 years ago
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Solve the expression and find the value of x.
vovangra [49]

\large\underline{\sf{Solution-}}

\sf \dfrac{x + 1}{10}  -  \dfrac{3(x - 1)}{5}  = 2

\sf\longmapsto  \dfrac{x + 1}{10}  -  \dfrac{3x - 3}{5}  = 2

\sf\longmapsto \dfrac{(x + 1) - 2(3x - 3)}{10}   = 2

\sf\longmapsto \dfrac{x + 1 - (6x - 6)}{10}  = 2

\sf\longmapsto  \dfrac{x + 1 - 6x + 6}{10}  = 2

\sf\longmapsto \dfrac{ - 5x + 7}{10}  = 2

\sf\longmapsto - 5x + 7 = 20

\sf\longmapsto - 5x = 20 - 7

\sf\longmapsto - 5x = 13

\sf\therefore x =  -  \dfrac{13}{5}

Hence, the value of x will be -13/5 respectively.

7 0
3 years ago
Read 2 more answers
X−7&lt;14<br><br> Options:<br><br> x&lt;7<br><br> x&gt;21<br><br> x&lt;21<br><br> x&gt;7
guajiro [1.7K]

This is a simple equation:

x - 7 < 14

x < 14 + 7

x < 21

→ Many people think that because there is not "=" sign they don't flip the sign of what in this case is -7. But actually, the symbols "<" and ">" act as the equal sign. This rule doesn't apply to positive number, only negative.


Hope it helped,


BioTeacher101


(If you have any questions, feel free to ask them in the comments)

6 0
3 years ago
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Consider the line integral Z C (sin x dx + cos y dy), where C consists of the top part of the circle x 2 + y 2 = 1 from (1, 0) t
pashok25 [27]

Direct computation:

Parameterize the top part of the circle x^2+y^2=1 by

\vec r(t)=(x(t),y(t))=(\cos t,\sin t)

with 0\le t\le\pi, and the line segment by

\vec s(t)=(1-t)(-1,0)+t(2,-\pi)=(3t-1,-\pi t)

with 0\le t\le1. Then

\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)

=\displaystyle\int_0^\pi(-\sin t\sin(\cos t)+\cos t\cos(\sin t)\,\mathrm dt+\int_0^1(3\sin(3t-1)-\pi\cos(-\pi t))\,\mathrm dt

=0+(\cos1-\cos2)=\boxed{\cos1-\cos2}

Using the fundamental theorem of calculus:

The integral can be written as

\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=\int_C\underbrace{(\sin x,\cos y)}_{\vec F}\cdot\underbrace{(\mathrm dx,\mathrm dy)}_{\vec r}

If there happens to be a scalar function f such that \vec F=\nabla f, then \vec F is conservative and the integral is path-independent, so we only need to worry about the value of f at the path's endpoints.

This requires

\dfrac{\partial f}{\partial x}=\sin x\implies f(x,y)=-\cos x+g(y)

\dfrac{\partial f}{\partial y}=\cos y=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\sin y+C

So we have

f(x,y)=-\cos x+\sin y+C

which means \vec F is indeed conservative. By the fundamental theorem, we have

\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=f(2,-\pi)-f(1,0)=-\cos2-(-\cos1)=\boxed{\cos1-\cos2}

3 0
3 years ago
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