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3 years ago

The product of 5 and a number x is 1/4. what is the value of x?

Mathematics

2 answers:

mars1129 [50]3 years ago

6 0

I had this same question nd the answer was

B. 1/20

solniwko [45]3 years ago

4 0

The mathematical expression is
5x = 1/4
Divide:
x = (1/4)/5 = (1/4)*5 = 5/4 (ANSWER)

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The square of a number is 12 less than 7 times the number. What is the number?

hjlf

Answer:

The number is either 3 or 4

Explanation:

Assume that the number we are looking for is x

The square of the number would be x²

7 times the number would be 7x

We are given that:

square of the number (x²) is 12 less than 7 times the number (7x)

Translating this into an equation, we would have:

x² = 7x - 12

Rearranging the quadratic equation:

x² - 7x + 12 = 0

Now, we factor the equation:

(x-4)(x-3) = 0

This means that:

either x-4 = 0 ..................> x = 4

or x-3 = 0 ........................> x = 3

Let's check if any of the solutions is an extrovert:

For x = 3 .............> (3)² = 7(3) - 12 .........> 9 = 21 - 12 .......> 9 = 9 .......> not extrovert

For x = 4 .............> (4)² = 7(4) - 12 .........> 16 = 28 - 12 .....> 16 = 16 ....> not extrovert

Since we have no restrictions on the number, therefore, both solutions would be accepted

Hope this helps :)

7 0

3 years ago

When you add the same number to each side of an equation, do you always get an equivalent equation? webasign?

CaHeK987 [17]

Yes you always do.

eg x - 2 = 8

x - 2 + 2 = 8 + 2

x = 10
if we plug x = 10 into the original equation we se that this fits:-

10 - 2 = 8

8 0

3 years ago

How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x

Fofino [41]

Answer:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

Step-by-step explanation:

We are given the function:

$f(x)=-4x^5-8x^3+12x$

And we want to finds its zeros.

Therefore:

$0=-4x^5-8x^3+12x$

Firstly, we can divide everything by -4:

$0=x^5+2x^3-3x$

Factor out an x:

$0=x(x^4+2x^2-3)$

This is in quadratic form. For simplicity, we can let:

$u=x^2$

Then by substitution:

$0=x(u^2+2u-3)$

Factor:

$0=x(u+3)(u-1)$

Substitute back:

$0=x(x^2+3)(x^2-1)$

By the Zero Product Property:

$x=0\text{ and } x^2+3=0\text{ and } x^2-1=0$

Solving for each case:

$x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}$

Therefore, our real and complex zeros are:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

4 0

3 years ago

S and Tare mutually exclusive events. Find P(sort) P(S) = 12% P(T) =27%

mario62 [17]

The value of the probability P(S or T) is 39%

<h3>How to determine the probability?</h3>

The probability values are given as:

P(S) = 12% P(T) =27%

For mutually exclusive events,

P(S or T) = P(S) + P(T)

This gives

P(S or T) = 12% + 27%

Evaluate the sum

P(S or T) = 39%

Hence, the value of the probability P(S or T) is 39%