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gtnhenbr [62]
3 years ago
10

Omar has a gift card for $40.00 at a gift shop. Omar wants to buy a hat for himself for $13.50. For his friends, he would like t

o buy souvenir bracelets, which are $3.25 each. All prices include taxes.
Which inequality can be used to solve for how many bracelets Omar can buy?
Mathematics
2 answers:
Natali [406]3 years ago
4 0

Answer:

He can buy 8 bracelets.

Step-by-step explanation:

$40.00 - $13.50 = 26.50 (40.0 - 13.5 = 26.5)

$26.50 * 8 = .5

WHAT I DID WAS I SUBTRACTED 13.50 FROM 40.00 THEN I KEPT DIVIDED A NUMBER TILL I COULDNT ANY MORE THIS WAS THEY SIMPLIEST WAY I COULD THINK OF THAT WOULDNT CONFUSE YOU IF YOU WANT A MORE MATHMATICAL WAY OF DOING THIS LET ME KNOW AND I CAN GET IT TO YOU.

HAVE A GOOD DAY!

Gnom [1K]3 years ago
3 0

Answer:

i) 3.25x ≤ 26.50

ii) Omar can buy 8 bracelets.

Step-by-step explanation:

Omar has a gift card for $40.00.

Omar bought a hat for $13.50

The remaining amount he has = $40.00 - $13.50 = $26.50

He would like to buy souvenir bracelets for his friends.

Each cost = $3.25

Let "x" be the number of bracelets can buy.

3.25x ≤ 26.50

Now we have to solve the inequality.

Dividing both sides by 3.25, we get

\frac{3.25x}{3.25} \leq \frac{26.50}{3.25}

x ≤ 8.15

The bracelets cannot be in decimal form.

So we have to round off to nearest whole number.

x ≤ 8

Therefore, Omar can buy 8 bracelets.

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Which of the following fractions is greater than -4/5 but less than -3/4
choli [55]

Answer:

B. -19/25

Step-by-step explanation:

You are looking for an answer that is greater than -4/5 (which is equal to -0.80) but less than -3/4 (which is equal to -0.75). So, you can easily convert the fractions to decimals by dividing.

-33/50 = -0.66, which is greater than -0.75, so it can be eliminated.

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7 0
3 years ago
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Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

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multiply by 3

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Answer:

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Step-by-step explanation:

we know that

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so

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