Louisa Hight 7 miles of a 21 mile trail what percent of the trail did she hike
1 answer:
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Answer:
see explanation
Step-by-step explanation:
I don't have graphing facilities but can give you the vertex and 1 other point.
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = -
y = - x² - 2x + 8 ← is in standard form
with a = - 1 and b = - 2 , then
x = - = - 1
Substitute x = - 1 into the equation for corresponding value of y
y = - (- 1)² - 2(- 1) + 8 = - 1 + 2 + 8 = 9
vertex = (- 1, 9 )
To obtain another point substitute any value for x into the equation
x = 0 : y = 0 - 0 + 8 , then (0, 8 ) is a point on the graph
x = 2 : y = - (2)² - 2(2) + 8 = - 4 - 4 + 8 = 0 then (2, 0 ) is a point on the graph
Answer:
h(d) = (17/3249)(-d² +114d)
Step-by-step explanation:
For this purpose, it is convenient to translate and scale a quadratic parent function so it has the desired characteristics. We can start with the function ...
f(x) = 1 -x² . . . . . . . has zeros at x = ±1 and a vertex at (0, 1)
We want to horizontally expand this function by a factor of 57, so we can replace x by x/57. We want to vertically scale it by a factor of 17, so the vertex is at (0, 17). Finally, we want to translate the function 57 m to the right, which requires replacing x with x-57. After these transformations, we have ...
f(x) = 17(1 -((x-57)/57)²) = (17/3249)(-x²+114x)
Using the appropriate function name and variable, we have ...
h(d) = (17/3249)(-d² +114d)
