Answer:
Math.way Algebra Calculator
Math.papa Algebra Calculator
Step-by-step explanation:
Im more of a "do it on a piece of paper" guy, but according to some comments, these are good sources.
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
Answer:
5) D
6) C
7) B
8) D
9) 109°
10) 83°
Step-by-step explanation:
5) In y=mx+b the slope is m. In perpendicular it'll be opposite, so the answer is D.
6) With the above knowledge about slope, the slope will be the same so it'll be C.
7) They are in the same position by different lines and will be corresponding aka B
8) These are adjacent angles because they are next to each other aka D
9) 180 - 71 = 109
10) They are correspodning so 83°
(slightly rushing so I hope this helped, have a nice day!)
Given:
The slope of a line is 
.
To find:
The lines in the options are parallel, perpendicular or neither parallel nor perpendicular to the given line.
Solution:
We know that the slopes of parallel lines are equal.
The slope of line Q and the slope of given line are same, i.e., . So, the line Q is parallel to the given line.
The slope of a perpendicular line is the opposite reciprocal of the slope of the line because the product of slopes of two perpendicular lines is -1.
The slope of a line is . It means the slope of the perpendicular line must be 
. So, the line N is perpendicular to the given line.
The slopes of line M and P are neither equal to the slope of the given line nor opposite reciprocal of the slope of the line.
Therefore, the lines M and P are neither parallel nor perpendicular.
Basically what you do is multiply the distance by the time, for example:
7 1/2 miles = 1/2 hour
so to get the amount of miles in one hour you get the miles and times it by two so it would go like this:
7 1/2 | 15 |
= | = |
1/2 | 1 |
then for one and a half you get the 1 hour answer and add the first one like this:
22.5 miles = 1 1/2 miles
and you continue that pattern!!! If you need more help just reply to this answer i'm in 7th grade so i can help with this stuff
