1) The coordinates of X are (1, -3)
2) When you reflect over a line parallel to the y-axis the x-coordinate does not change, so the x-coordinate of X' is 1.
3) The vertical distance between the point X (1, - 3) and the line y = 1 is 1 - (-3) = 1 + 3 = 4.
4) The vertical distance of the point X' has to ve the same, 4, and the point X' will be 4 units over the line y = 1. That leads to y = 1 + 4 = 5.
So the y-coordinate of the point X' is 5.
5) Conclusion the coordinates of the point X' are x = 1, y = 5, i.e.point (1,5)
Answer:
8^-32
Step-by-step explanation:
Subtract 49 by its negative so now
x^2-16x=-49
then move -16 so
x^2=-49+16x
then add -49 and 16 so then you get
X^2+your answer)
then find the square root because this was in exponential form so find the square root of x^2 and of your answer so
X= Your answer
do the work
