Answer:
numbwer 8 is 44.04
Step-by-step explanation:
plz put brainliest
Answer:
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error:

For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is
We need a sample size of at least n, in which n is found M = 0.04.







With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.
Answer:
I think the closest would be 41.5%
Step-by-step explanation:
If you take the number of passengers left on the plane and divide by the total number of passengers that were on the plane in the beginning, you would get 58.5%. That's the % of how many people are left on the plane. So, you would then do 100%-58.5% to get the answer 41.5%. Hope this helps! :)
Answer:
∠1=a+b/2
∠1=37+25/2
∠1=31
Answer: C) 31
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Hope it helps...
Have a great day!!!
5 because it says 11-16 which is one number before 15. dollars