Question

Write, in slope intercept form, the equation of the line that passes through (8, -9) and has a slope of -5/4.

Answer 1

Answer:

The equation in the slope-intercept form will be:

$y=-\frac{5}{4}x+1$

Step-by-step explanation:

Given

• slope = m = -5/4

• point = (8, -9)

As we know that the equation of a line in point-slope form is

$y-y_1=m\left(x-x_1\right)$

substituting the values m = -5/4 and point = (8, -9)

$y-\left(-9\right)=\frac{-5}{4}\left(x-8\right)$

$y+9=\frac{-5}{4}\left(x-8\right)$

Writing the equation in slope-intercept form

$y=mx+b$

where m is the slope, and b is the y-intercept

so the equation of the line in slope-intercept form becomes

$y+9=\frac{-5}{4}\left(x-8\right)$

subtract 9 from both sides

$y+9-9=\frac{-5}{4}\left(x-8\right)-9$

$y=-\frac{5}{4}x+1$

Therefore, the equation in the slope-intercept form will be:

$y=-\frac{5}{4}x+1$