Observation that we can make is min = 10, max = 19, range = 9, Maximum frequency of a number is 12, Average = 12.9, median = 12, mode = 12 it is slightly skewed on the right.

Step-by-step explanation:

It is imperative to create a data in a tabular column before analyzing.
Once the data is created use tally marks or frequency distribution.
Frequency distribution helps the data to provide occurrence of event.
Very important to number which is a counting numbers are discrete.
Continuous of data are ones which are in decimal.
Descriptive statistics is the 1st level of Statistics.
It finds, where the data stands. Minimum, Maximum is understandable.
Range is at what level data is expanded.
Average is the one numeric of a number.
Median is the mid point of data
Mode is the repetitive number of the data.
Skewness is whether data is having extreme directions.

5 0

3 years ago

In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha

siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95, P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

$P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043$

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0

3 years ago

Express 2/27 as the sum of two unit fractions

loris [4]

Answer:

1/27+1/27

Step-by-step explanation:

8 0

3 years ago