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Mrac [35]
3 years ago
10

Consider the enlargement of the triangle and use the measurements to calculate the scale factor.

Mathematics
2 answers:
pickupchik [31]3 years ago
8 0

Answer: 8

Step-by-step explanation:

Kay [80]3 years ago
3 0

Answer:

40

Step-by-step explanation:

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Write an expression that is equivalent to 1/3(24p-33) -iready
Leno4ka [110]

Answer:

664434444455667765433344455576

5 0
2 years ago
Suppose the rate of type II diabetes in 40- to 59-year-olds is 7% among Caucasians, 10% among African-Americans, 12% among Hispa
melomori [17]

Answer:

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

Step-by-step explanation:

We have these following rates of type II diabetes:

7% among Caucasians

10% among African-Americans

12% among Hispanics

5% among Asian-Americans.

The ethnic distribution of Houston is:

30% Caucasian

25% African-American

40% Hispanic

5% Asian-American

What is the overall probability of type II diabetes among 40- to 59-year-olds in Houston?

P = P_{1} + P_{2} + P_{3} + P_{4}

P_{1} is the probability of finding a Caucasian with type II diabetes in Houston. So it is 7% of 30%.

P_{1} = 0.07*0.30 = 0.021

P_{2} is the probability of finding an African-American with type II diabetes in Houston. So it is 10% of 25%.

P_{2} = 0.1*0.25 = 0.0215

P_{3} is the probability of finding a Hispanic with type II diabetes in Houston. So it is 12% of 40%.

P_{3} = 0.12*0.40 = 0.048

P_{4} is the probability of finding an Asian-American with type II diabetes in Houston. So it is 5% of 5%.

P_{3} = 0.05*0.05 = 0.0025

P = P_{1} + P_{2} + P_{3} + P_{4} = 0.021 + 0.0215 + 0.048 + 0.0025 = 0.093

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

4 0
4 years ago
6b.) Graph the given points C(-3, 2) and D(6, 2) and find the slope.<br> What is the slope?
White raven [17]
I think y=2 there both on the 2 y intercept straight from each Other
6 0
3 years ago
Please help me find out what the question marks are
quester [9]
Question a

g(x) times \sqrt{x-5}=\sqrt{x^2-5}
divide both sides by √(x-5)
g(x)=\frac{\sqrt{x^2-5}}{\sqrt{x-5}}
g(x)=\frac{(\sqrt{x-5})(\sqrt{x^2-5})}{x-5}
g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}


question b
g(x) \space\ times \space\ 1+\frac{1}{x}=x
divide both sides by 1+1/x
g(x)=\frac{x}{1+\frac{1}{x}}
times by x/x
g(x)=\frac{x^2}{x+1}


question c
\frac{1}{x} \space\ times \space\ f(x)=x
times both sides by x
f(x)=x^2


question d
the (f*g)(x) collumn seems to have a domain of only x is greater than or equal to 0?
so maybe we squared the whole thing, ya
wait
ah, ya
basically
|x|=(\sqrt{x})^2=(\sqrt{x})(\sqrt{x})
so f(x)=√x


a. g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}
b. g(x)=\frac{x^2}{x+1}
c.f(x)=x^2
d. f(x)=\sqrt{x}
3 0
4 years ago
Read 2 more answers
On a road trip, you drive about 70 miles per hour and your friend drives about 60 miles per hour. The plan is to drive less than
lord [1]

Answer: The answer is 0 hours and 10 hours.


Step-by-step explanation:  Given that me and my friend are on a road trip. My speed is 70 miles per hour and my friend's speed is 60 miles per hour. Our plan is to drive less than 15 hours and at least 600 miles each day.

Also, my friend will drive more hours than me.

Let, 'x' and 'y' be the number of hours drove by me and my friend respectively. Then, according to the given information, we have the following inequalities.

y>x,\\\\x+y

When we plot these inequalities in a graph paper, we can see in the attached figure, where the common shaded region gives the solution set,  one of the solution is point 'P', given by

x = 0 and y = 10.

This solution satisfy all the three conditions given above.

Thus, one of the solution is - I will drive for 0 hours and my friend will drive for 10 hours.



8 0
3 years ago
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