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3 years ago

PLEASE ANSWER! Giving away 15 points if someone answers!!!

Mathematics

2 answers:

aleksley [76]3 years ago

7 0

I think it would be C and D but I'm not sure Ik I ain't A or B bc it doesn't tell us how much the almonds r

cupoosta [38]3 years ago

4 0

Answer:

Option A and C.

Step-by-step explanation:

Venetta buys 2 pounds of pistachios and 3 pounds of almonds for $48.

The cost of pistachios $4 more per pound than the almonds.

Let the cost of almonds be a

Therefore, cost of pistachios p = 4 + a ------(1)

Venetta bought 2 pound of pistachios and 3 pounds of almonds for $48, so the equation will be

2p + 3a = 48 -----------(2) [we will substitute equation 1]

2(4+a) + 3a = 48 --------------(3)

(2 × 4) + (2 × a) + 3a = 48

2a + 3a + 8 = 48

5a + 8 = 48

5a = 48 - 8

5a = 40

a = 40/5

a = 8

hence the cost of almonds are $8 per pound.

the cost of pistachios is 4 + 8 = $12 per pound.

Option A and C is the correct answer.

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12-2x=-2(y-x), solve for x

Romashka [77]

Solve: 12 - 2x = -2(y - x)

Steps:

1. Expand -2(y - x): -2y + 2x

12 - 2x = -2y + 2x

2. Then subtract 12 from both sides

12 - 12 - 2x = -2y + 2x - 12

3. Simplify,

-2x = -2y + 2x - 12

4. Then, subtract 2x from both sides

-2x - 2x = -2y + 2x - 2x - 12

5. Simplify,

-4x = -2y - 12

6. Then, divide both sides by -4

-4x/-4 = -2y/-4 - 12/-4

7. Simplify,

x = 1/2y + 3 <======= <em>Answer</em>

Hope this helped!!!!

8 0

3 years ago

Noel bought a 10 ounce box of cereal for $1.63 What was the cost per ounce?

Vilka [71]

The answer that i got was .163 because i divided the 1.63 dollars total by the total ounces (10) and got .163

8 0

3 years ago

Can I get help answering this question? It's a derivatives question, further info in the attachment.

Nadusha1986 [10]

$\bf f(x)=|3+9x|\implies f(x)=\sqrt{(3+9x)^2}\implies f(x)=[(3+9x)^2]^{\frac{1}{2}}
\\\\\\
\cfrac{dy}{dx}=\stackrel{chain~rule}{\cfrac{1}{2}[(3+9x)^2]^{-\frac{1}{2}}\cdot 2(3+9x)\cdot 9}\implies \cfrac{dy}{dx}=\cfrac{9(3+9x)}{[(3+9x)^2]^{\frac{1}{2}}}
\\\\\\
\cfrac{dy}{dx}=\cfrac{27+81x}{|3+9x|}\\\\
-------------------------------$

$\bf \textit{left-hand derivative at }x=-\frac{3}{9}\implies \cfrac{27+81x}{-(3+9x)}
\\\\\\
\cfrac{27+81\left( -\frac{3}{9} \right)}{-3-9\left( -\frac{3}{9} \right)}\implies \cfrac{27-27}{-3+3}\implies \stackrel{unde fined}{\cfrac{0}{0}}\\\\
-------------------------------\\\\
\textit{right-hand derivative at }x=-\frac{3}{9}\implies \cfrac{27+81x}{+(3+9x)}
\\\\\\
\cfrac{27+81\left( -\frac{3}{9} \right)}{3+9\left( -\frac{3}{9} \right)}\implies \cfrac{27-27}{3-3}\implies \stackrel{unde fined}{\cfrac{0}{0}}$

8 0

3 years ago

Somebody answer plz and thanks if u do

Katarina [22]

Answer:

y=-3, x=3

Step-by-step explanation:

step by step in picture

everything you asked for is in the picture