Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.

Multiply both sides by 100.


Divide both sides by 50.


The amount invested at 7% is
.
The amount invested at 8% is

The amount invested at 9% is

Thus, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
Answer:
सामाजिक अध्ययन र जिवनोपयोगी शिक्षाको महत्व दसांउनुहोस
Answer:
I think it’s 105
Step by step explanation:
I hope this helped in some kind of way.
Answer:
71°
Step-by-step explanation:
31-3x+19x-5=90
16x=90-26
16x=64
x=4
m<R=19x-5 = 19(4)-5 = 76-5 = 71
Answer:
The value of log 43is 1.633
Step-by-step explanation:
Explanation:
Suppose you know that:

Then note that:

So

We know that the error is approximately:

So we can confidently give the approximation:
