Ask question

Ask question

All categories

3 years ago

8

A parking garage near Cody's house is 4 stories tall. There are 68 open parking spots on the first level. There are 2 more open

parking spots on the second level than on the first level, and there are 3 more open parking spots on the third level than on the second level. There are 11 open parking spots on the fourth level. How many open parking spots are there in all?

1 answer:

Aleonysh [2.5K]3 years ago

5 0

Answer:

5,032

Step-by-step explanation:

You take 68 and multiply it by 2. Then you take the product that you got from there and multiply it by three. take that number from there; multiply it by eleven. Woot-Woot! Answer!

*~ I hope this helps!!~*

You might be interested in

Norman and Suzanne own 34 shares of a fast food restaurant stock and 70 shares of a toy company stock. At the close of the marke

puteri [66]

1488=34F+70T
F=T+30
this is the system of equations heeded o solve this problem. because we are given that both stocks together are equal to $1488. we are also told that here are 34 share of the fast food stock. and there are 70 shares of the toy stock. each share has an unknown value. this is where i get the. 34F and 70T. we are told that one fast food share (F) is equal to $30 more than the toy share (T) so f=t+30.
solve he system of equations. they give you the value of f is t+30. so plug that into the original equation (1488=34F+70T) in placeof F so the new equation is 1488=34(T+30)+70T
combine like terms and solve for T. plug the value of T into the original equation and solve for F. check your work by plugging both of your answers (answer for F and answer for T) into the original equation.

6 0

3 years ago

3 out of five picks are orange . If 12 picks are orange , how many picks are there in all?

tekilochka [14]

20 picks in total .

8 0

3 years ago

A³b² a²b simplify the following expression

liberstina [14]

Answer:

$a^{5}$ $b^{3}$

Step-by-step explanation:

The law of indices can be used to simplify mathematical expressions involving arithmetical operation on variables with powers.

$a^{m}$ x $a^{n}$ = $a^{(m+n)}$

Thus, the given expression can be simplified as follows:

a³b² a²b = a³ x a² x b² x $b^{1}$

= $a^{3+2}$ x $b^{2+1}$

= $a^{5}$ $b^{3}$

Thus,

a³b² a²b = $a^{5}$ $b^{3}$

7 0

3 years ago

A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0

3 years ago

Please answer the following;

34kurt

The Surface area of the cube will be 433.5 square feet. Then the correct option is C.

<h3>What is a surface area of a cube?</h3>

Suppose that: The side length of the considered cube is L units. Then, we get:

Surface area of that cube = 6L² square units.

Bella is wrapping a cube shape box that measures 8.5 inches along each side.

The edge length of the cube is 8.5 meters.

Then the Surface area of the cube will be

Surface area = 6 x 8.5²

Surface area = 6 x 72.25

Surface area = 433.5 square feet

The Surface area of the cube will be 433.5 square feet.

Then the correct option is C.

More about the surface area of the cube link is given below.

brainly.com/question/13789496

#SPJ1

6 0

2 years ago