Answer:
A. 121 ⇒ III. 11
B. 64 ⇒ II. 4 and IV. 8
C. 27 ⇒ I. 3
D. 125 ⇒ V. 5
E. 16 ⇒ II. 4
Step-by-step explanation:
Let us find the correct answer
∵ 121 = 11 × 11
∴ The square root 121 is 11
∴ A. 121 ⇒ III. 11
∵ 64 = 8 × 8
∴ The square root of 64 is 8
∵ 64 = 4 × 4 × 4
∴ The cube root of 64 is 4
∴ B. 64 ⇒ II. 4 and IV. 8
∵ 27 = 3 × 3 × 3
∴ The cube root of 27 is 3
∴ C. 27 ⇒ I. 3
∵ 125 = 5 × 5 × 5
∴ The cube root of 125 is 5
∴ D. 125 ⇒ V. 5
∵ 16 = 4 × 4
∴ The square root of 16 is 4
∴ E. 16 ⇒ II. 4
Answer:
x = 17 and y = 37
Step-by-step explanation:
Let the numbers be x and y.
y = 3 + 2x
xy = 629
substituting y in the second equation we get
x(3+2x) = 629
3x + 2
= 629
2
+ 3x - 629 = 0
Solving a quadratic equation by using its formula:
x = [-3 ±√(9-4(2)(-629)] / 4
x = [-3 ± √5041] / 4
x = [-3 ± 71] / 4
x = 17 and 
Ignore the negative number in x and just use x = 17 in the first equation we get
y = 3 + 2(17) = 37
Answer:
Please be more clear and I might be able to help
Step-by-step explanation: