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3 years ago

Complete the following.

Mathematics

1 answer:

Gnom [1K]3 years ago

5 0

Answer:

Step-by-step explanation:

1) From the given right angle triangle,

22 represents the hypotenuse of the right angle triangle.

With m∠21 as the reference angle,

x represents the opposite side of the right angle triangle.

To determine x, we would apply

the Sine trigonometric ratio.

Sin θ = opposite side/hypotenuse. Therefore,

Sin 21 = x/22

x = 22 Sin 21 = 22 × 0.3584

x = 7.9

2) From the given right angle triangle,

RS represents the hypotenuse of the right angle triangle.

With m∠S as the reference angle,

x represents the adjacent side of the right angle triangle.

To determine x, we would apply

the Cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos 33 = x/15

x = 15 Cos 33 = 15 × 0.8387

x = 12.6

3) From the given right angle triangle,

AB represents the hypotenuse of the right angle triangle.

With m∠A as the reference angle,

x represents the adjacent side of the right angle triangle.

y represents the opposite side of the right angle triangle.

To determine x, we would apply

the Cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos 32 = x/10

x = 10 Cos 32 = 10 × 0.848

x = 8.5

To determine y, we would apply

the Sine trigonometric ratio.

Sin θ = opposite side/hypotenuse. Therefore,

Sin 32 = y/10

y = 10 Sin 32 = 10 × 0.5299

y = 0.53

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Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

4 0

3 years ago

Need help with this

snow_tiger [21]

Answer:

x y

15 -1

12 0

9 1

6 2

3 3

0 4

Step-by-step explanation:

This is a function table. For a linear function, find the average rate of change between the listed points called slope. Then use the slope to fill in other inputs and outputs for the function.

$m = \frac{y_2-y_1}{x_2-x_1}=\frac{4-0}{0-12} =\frac{4}{-12} =- \frac{1}{3}$

This means for every 3 units made in the input, the function moves down 1 output.

x y

15 -1

12 0

9 1

6 2

3 3

0 4

6 0

3 years ago

NEED HELP ASAP!!

Ganezh [65]

Answer:

graph 3 graph 1 graph 2 graph 4

6 0

3 years ago

Two groups of students were asked how far they lived from their school. The table shows the distances in miles: Group A (distanc

iogann1982 [59]

The mean is equal for Group A and Group B.

<h2>Given </h2>

Two groups of students were asked how far they lived from their school.

The table shows the distances in miles:

Group A (distance in miles) 1 1.5 3.03 3.2 2.8 1.5 1.8 2.5 2.2

Group B (distance in miles) 2 2.5 3.23 1.3 1.8 2.4 3 1.5 1.8

The mean of any data set or observation is equal to the sum of all the observations and divided by the number of observations.

The formula used to calculate the mean is;

$\rm Mean = \dfrac{Sum \ of \ all \ observation}{Number \ of \ obrservation}$

The mean of group A is;

$\rm Mean = \dfrac{Sum \ of \ all \ observation}{Number \ of \ obrservation}\\\\\rm GroupA \ mean = \dfrac{1 + 1.5 + 3.03 + 3.2 + 2.8 + 1.5 + 1.8 + 2.5 + 2.2}{9 }\\\\\rm Group A \ mean=\dfrac{ 19.53}{9}\\\\ Group A \ mean = 2.17$

The mean of group B is;

$\rm Mean = \dfrac{Sum \ of \ all \ observation}{Number \ of \ obrservation}\\\\\rm Group B \ mean = \dfrac{2 + 2.5 + 3.23 + 1.3 + 1.8 + 2.4 + 3 + 1.5 + 1.8}{9} \\\\Group B \ mean = \dfrac{19.53}{9}\\\\ Group B \ mean = 2.17$

Hence, the mean is equal for Group A and Group B.

To know more about Mean click the link given below.

brainly.com/question/12513463

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2 years ago

Are these fractions equivalent 1/11 2/22

weqwewe [10]

Answer:

yes

Step-by-step explanation

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3 years ago

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