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QveST [7]
2 years ago
8

The ratio of rolls of wrapping paper to presents is 2 to 16.

Mathematics
2 answers:
Vilka [71]2 years ago
5 0
8 presents can be wrapped per roll
son4ous [18]2 years ago
3 0
I believe 8 presents
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(7x-49x^2)/(7x) can smeone solve this? Thank you! I hope you have a great day!
svp [43]

Answer:

x = 1/7

Step-by-step explanation:

\frac{(7x-49x^2)}{7x}\\\\\frac{7x(1-7x)}{7x} \\\\1-7x=0\\\\1=7x\\\\

x = 1/7

3 0
3 years ago
Jay Spring pays $350.00 annually for his health insurance. This is 1/3 of the total cost of the premium; his company pays the re
VashaNatasha [74]
$1,800 (10%) = $180 
jay pays 10% of the expenses beyond the deductible so you multiply the amount beyond the deductible by 10%.
$1,800 - $180 = $1,620 
or
$1,800 (90%) = $1,620
you subtract what jay pays from the total or you multiply the total by 90%

jay pays $180 of the expenses past the deductible (not including his $200 deductible) and his insurance company pays $1,620. 
4 0
3 years ago
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Mrs. Chauvet has an unfair number cube that lands with 6 facing up 40% of the time. Let X = the number of times that she rolls a
goldfiish [28.3K]

Answer:

P(X<1) = .216         P(X</=1) = .648

Step-by-step explanation:

its right

5 0
2 years ago
Find the arc length and area of a sector with radius R =60 inches and central angle equals 30° round your answer to the nearest
Black_prince [1.1K]

Answer:

(a)31.42 inches

(b)942.48 Square Inches

Step-by-step explanation:

Given a sector of a circle with the following dimensions:

Radius of the circle =60 inches

Central Angle of the sector =30°

(a)Arc Length

Arc Length =\dfrac{\theta}{360^\circ}X2\pi r

=\dfrac{30}{360^\circ}X2*60*\pi\\\\=10\pi\\\\=31.42$ Inches (correct to the nearest hundredth)

(b)Area of the sector

Area of the sector =\dfrac{\theta}{360^\circ}X\pi r^2

=\dfrac{30}{360^\circ}X\pi*60^2\\\\=300\pi\\\\=942.48$ Square Inches (correct to the nearest hundredth)

3 0
3 years ago
Read 2 more answers
Please answer this question asap
lukranit [14]

Answer:

Use the formula

P(X,y) ___y=x__(Reflection)_____P'(y,x)

I think it will help you.

8 0
2 years ago
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