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GalinKa [24]
4 years ago
8

Simplify please! find the solution.

Mathematics
1 answer:
spin [16.1K]4 years ago
5 0
1 / ( r + 3 ) = ( r + 4 ) / ( r - 2 ) + 6 / ( r - 2 ); where r isn't -3 and 2;

1 / ( r + 3 ) =  ( r + 10 ) / ( r - 2 )

r - 2 = ( r + 10 )*( r + 3)

r - 2 = r ^2 + 13*r + 30

r^2 + 12 * r + 32 = 0

r^2 + 4*r + 8*r + 32 = 0

r( r + 4 ) + 8( r + 4 ) = 0

( r + 4 )*( r + 8 ) = 0

r + 4 = 0 => r = - 4;
or
r + 8 = 0 => r = - 8;

The solutions are : -4 ; -8.
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Here is the answer to ur question :) Hope this helps!

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The tens digit is missing from the three-digit number 8 _ 9. If the tens digit is to be randomly selected from the ten different
PIT_PIT [208]

Step-by-step explanation:

Only 1 number works. 1 will make 819 which is divisible by 9.

Since it is 1 of ten numbers can go in the blank, the answer is 1/10 which is 0.1

The 10 number choices are

0,1,2,3,4,5,6,7,8,9

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A coral reef grows 0.11m every week. How much does it grow in 15 weeks?
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4 years ago
The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of
ser-zykov [4K]

Answer:

p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}, for r_{1} = 0

Step-by-step explanation:

The general form of quintic-order polynomial is:

p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f

According to the statement of the problem, the polynomial has the following roots:

p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)

Then, some algebraic handling is done to expand the polynomial:

p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)

p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x

If r_{1} = 0, then:

p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}

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3 years ago
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Answer:

36 i think

Step-by-step explanation:

6 0
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