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vaieri [72.5K]
2 years ago
9

The relationship between a bacteria population p, in thousands, and time d, in days, since it was measured to be 1,000 can be re

presented by the equation .
Select all statements that are true about the situation.





© 2019 Illustrative Mathematics. All Rights Reserved.


Select all that apply:
A: Each day, the bacteria population grows by a factor of 2
B: The equation p=2^d also defines the relationship between the population in thousands and time in days
C: The population reaches 7,000 after log2(7,000) days
D: The expression log2(10) tells us when the population reaches 10,000.
E: The equation d=log2(p) represents a logarithmic function
F: The equation 7=log2(128) tells us that the population reaches 128,000 in 7 days.
Mathematics
1 answer:
klemol [59]2 years ago
3 0

The expression log₂(10) tells us when the population reaches 10,000 and the equation 7 = log₂(128) tells us that the population reaches 128,000 in 7 days.

<h3>What is an exponential function?</h3>

An exponential function is in the form:

y = abˣ

Where a is the initial value of y and b is the multiplication factor.

Let p represent the bacteria population in thousand after d days.

Since each day, the bacteria population grows by a factor of 2, hence:

p=2^d

Hence, d = log₂p represents a logarithmic function

The expression log₂(10) tells us when the population reaches 10,000 and the equation 7 = log₂(128) tells us that the population reaches 128,000 in 7 days.

Find out more on exponential function at: brainly.com/question/12940982

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Which logarithmic equation is equivalent to the exponential equation below?
aleksandr82 [10.1K]

Option B: \ln 6=5 x is the correct answer.

Explanation:

The exponential equation is e^{5 x}=6

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7 0
3 years ago
For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
Tema [17]

Answer:

Number of cheaper dresses sold  is 35

Number of expensive  dresses sold  is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of  expensive dresses = $140

Total cost of  the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) +  (Number of Expensive dresses X cost of  expensive dress)  =  $5250

x \times90 +y \times 140 = 5250=  $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

1800 + 230y = 5250

230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0
3 years ago
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