Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day
.
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a. 
b. 
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:

The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days


Solving (b); The value of E when d = 30.
Substitute 30 for d in 



<em>Hence, there are 5000kwh left after 30 days</em>
Its going to be 4 .............
Given,
The expression is:

By using the middle term splitting method,

Hence, the factor is (x-(7+sqrt(33)/4)) (x+(7+sqrt(33)/4)).
Answer:
D: 5 : 8 and 20 : 32
Step-by-step explanation:
A is incorrect because 3 x 1.33 = 4 and 4 x 1.25 = 5.
B is incorrect because 10 x 1.6 = 16 and 12 x 1.5 = 18.
C is incorrect because 7 x 1.428 = 10 and 10 x 1.4 = 14.
D is correct because 5 x 4 = 20 and 8 x 4 = 32.
another way of solving the ratio answers is by putting them in a fraction 5/8 = .625 and also does 20/32 = .625.....
Easy right!?
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