The domain of the relation is 7,13 and the range of the relation is 4,20. I hope this helps.
Answer:
Step-by-step explanation:
STEP
1
:
Equation at the end of step 1
(((2 • (x3)) - 3x2) - 23x) + 12
STEP
2
:
Equation at the end of step
2
:
((2x3 - 3x2) - 23x) + 12
STEP
3
:
Checking for a perfect cube
3.1 2x3-3x2-23x+12 is not a perfect cube
Trying to factor by pulling out :
3.2 Factoring: 2x3-3x2-23x+12
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: -23x+12
Group 2: 2x3-3x2
Pull out from each group separately :
Group 1: (-23x+12) • (1) = (23x-12) • (-1)
Group 2: (2x-3) • (x2)
Bad news !! Factoring by pulling out fails :
The groups have no common factor and can not be added up to form a multiplication.
Answer:
Step-by-step explanation:Simplifying
0 = 2.5y + -20
Reorder the terms:
0 = -20 + 2.5y
Solving
0 = -20 + 2.5y
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '-2.5y' to each side of the equation.
0 + -2.5y = -20 + 2.5y + -2.5y
Remove the zero:
-2.5y = -20 + 2.5y + -2.5y
Combine like terms: 2.5y + -2.5y = 0.0
-2.5y = -20 + 0.0
-2.5y = -20
Divide each side by '-2.5'.
y = 8
Simplifying
y = 8
SO the answer is y=8 I think srry if i get it wrong
As a fraction = 1*83/100
As an improper fraction = 183/100
Answer:
£25
Step-by-step explanation:
100 - 15 = 85
53.55 ÷ 0.85 = 63
63 - 38 = 25