The length of BC is 4.674 m
<u>Explanation:</u>
Given:
Angle A = angle B = 90°
AD = 2.1 m
AB = 1.9 m
CD= 3.2 m
An image is inserted for the reference
According to the figure,
a is the base
b is the height
c is the hypotenuse
Using pythagoras theorm:
a² + b² = c²
a² + (1.9)² = (3.2)²
a² + 3.61 = 10.24
a² = 6.63
a = 2.574
BC = 2.1 + 2.574
BC = 4.674m
Therefore, the length of BC is 4.674 m
1.7 s<span>, then the </span>velocity<span> of the </span>baseball<span> is 22.35 </span>m/s<span> toward first base. hope this helps.</span>
Answer:
2
Step-by-step explanation:
Calculate the distance (d) using the distance formula
d = √(x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (- 2, 4) and (x₂, y₂ ) = (4, - 6)
d = 
= 
= 
= 
= 
= 
× = 2
The graph of y > mx, where m > 0, consists of a dashed line and a shaded half plane. The line has a positive slope and passes through the origin. The shaded half plane is above the line.
Answer:
A score of 117 is needed, which Is not possible since the test is over 100.
Step-by-step explanation:
The other 3 scores are 85, 94,84 . Let's x be the 4th score he must score.
Therefore ( 85 + 94 + 84 + X)/4 =95
Then 263+X /4 =95
Cross mutiplying 4*95=263+X
Therefore X= 380-263
X= 117 which is not possible since the test score is over 100.
