The result of simplifying the expression (x²/x⁻¹¹)¹/₃ using the exponent rules is ![\sqrt[3]{}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%7D)
(x¹³)
To solve this exercise we have to resolve algebraic operations following the exponent rules.
(x²/x⁻¹¹)¹/₃
Using the quotient rule that indicates that: the exponent result will be the subtraction of these exponents, we have:
(x⁽²⁻⁽⁻¹¹⁾)¹/₃
(x⁽²⁺¹¹⁾)¹/₃
(x¹³)¹/₃
Using the power of a power rule that indicates that: the exponent result will be the multiplication of these powers, we have:
x⁽¹³*¹/₃⁾
x⁽¹³/₃⁾
As we have a fractional exponent, you must convert the exponent to root:
(x¹³)
<h3>What is an exponent?</h3>
In mathematics an exponent is the number of time that a number, called (base) is multiplied by itself. It is also called, power or index.
Example: 3² = 3*3 = 9
Learn more about exponent at: brainly.com/question/847241
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Answer:
(x -6)^2 +(y -3)^2 = 2
Step-by-step explanation:
The midpoint (C) is the center of the circle:
C = ((5, 4) +(7, 2))/2 = ((5+7)/2, (4+2)/2) = (6, 3)
A circle with center (h, k) that goes through point (a, b) can be written as ...
(x -h)^2 +(y -k) ^2 = (a -h)^2 +(b -k)^2
Using the values for this problem, we get ...
(x -6)^2 +(y -3)^2 = (5 -6)^2 +(4 -3)^2
(x -6)^2 +(y -3)^2 = 2
Answer:
2(5+y)+2y=38 10+2y+2y=38 4y=28 y=7 i think
Step-by-step explanation:
9514 1404 393
Answer:
(a) x = (3 -ln(3))/5 ≈ 0.819722457734
(b) y = 10
Step-by-step explanation:
(a) Taking the natural log of both sides, we have ...
2x +1 = ln(3) +4 -3x
5x = ln(3) +3 . . . . . . . . add 3x-1
x = (ln(3) +3)/5 ≈ 0.820
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(b) Assuming "lg" means "log", the logarithm to base 10, we have ...
log(y -6) +log(y +15) = 2
(y -6)(y +15) = 100 . . . . . . . taking antilogs
y^2 -9x -190 = 0 . . . . . . . . eliminate parentheses, subtract 100
(y -19)(y +10) = 0 . . . . . . . . factor
The values of y that make these factors zero are -19 and 10. We know from the first term that (y-6) > 0, so y > 6. That means y = -19 is an extraneous solution.
The solution is ...
y = 10
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When solving equations using a graphing calculator, it often works well to define a function f(x) such that the solution is f(x) = 0, the x-intercept(s). That form is easily obtained by subtracting the right side of the equation from both sides of the equation. In part (a) here, that is ...
f(x) = e^(2x+1) -3e^(4-3x)
