All categories

3 years ago

Use completing the square to solve for x in the equation (x minus 12) (x 4) = 9.

Mathematics

1 answer:

Sindrei [870]3 years ago

6 0

Answer:

By using completing the square method, equation (x - 12) (x + 4) = 9 can be solved as x = (4 + √ 73) or (4 - √ 73)

You might be interested in

If f(x) = g(x) + 4, find g(x) for f(x) = 3x + 2<br> Can someone please help?

yawa3891 [41]

Answer:

see below

Step-by-step explanation: 5 23 15 03

f(x) = g(x) + 4 find g(x) for f(x) = 3x + 2

sub f(x) = 3x + 2 into f(x) = g(x) +4

3x + 2 = g(x) + 4

3x + 2 - 4 = g(x) + 4 - 4

3x - 2 = g(x)

5 0

3 years ago

Read 2 more answers

Find the measure of each angel in the isosceles trapezoid

Naily [24]

There go your answer to your question

8 0

4 years ago

-6x+y=8<br> 5x+y=8 <br><br> using elimination method

asambeis [7]

Answer:

x=0, y=8. (0, 8).

Step-by-step explanation:

-6x+y=8

5x+y=8

-----------

-6x+y=8

-(5x+y)=-8

--------------

-6x+y=8

-5x-y=-8

-------------

-11x=0

x=0/-11

x=0

5(0)+y=8

0+y=8

y=8-0

y=8

7 0

4 years ago

Find the equation of the line that passes through (0, -3) and is parallel to

Tresset [83]

Hey there!

$\\$

Answer:

$\green{\boxed{\red{\bold{\sf{y = \dfrac{7}{6}x - 3}}}}}$

$\\$

Explanation:

To find the equation of a line, we first have to determine its slope knowing that parallel lines have the same slope.

Let the line that we are trying to determine its equation be $\: \sf{d_1} \:$ and the line that is parallel to $\: \sf{d_1} \:$ be $\: \sf{d_2} \:$ .

$\sf{d_2} \:$ passes through the points (9 , 2) and (3 , -5) which means that we can find its slope using the slope formula:

$\sf{m = \dfrac{\Delta y}{\Delta x} = \dfrac{\green{y_2} - \orange{y_1}}{\red{x_2} - \blue{x_1 }}}$

$\\$

⇒Subtitute the values :

$\sf{(\overbrace{\blue{9}}^{\blue{x_1}}\: , \: \overbrace{\orange{2}}^{\orange{y_1}}) \: \: and \: \: (\overbrace{\red{3}}^{\red{x_2}} \: , \: \overbrace{\green{-5}}^{\green{y_2}} )}$

$\implies \sf{m = \dfrac{\Delta y}{\Delta x} = \dfrac{\green{-5} - \orange{2}}{\red{ \: \: 3} - \blue{9 }} = \dfrac{ - 7}{ - 6} = \boxed{ \bold{\dfrac{7}{6} }}}$

$\sf{\bold{The \: slope \: of \: both \: lines \: is \: \dfrac{7}{6}}}$ .

Assuming that we want to get the equation in Slope-Intercept Form, let's substitute m = 7/6:

Slope-Intercept Form:

$\sf{y = mx + b} \\ \sf{Where \: m \: is \: the \: slope \: of \: the \: line \: and \: b \: is \: the \: y-intercept.}$

$\implies \sf{y = \bold{\dfrac{7}{6}}x + b}$ $\\$

We know that the coordinates of the point (0 , -3) verify the equation since it is on the line $\: \sf{d_1} \:$ . Now, replace y with -3 and x with 0:

$\implies \sf{\overbrace{-3}^{y} = \dfrac{7}{8} \times \overbrace{0}^{x} + b} \\ \\ \implies \sf{-3 = 0 + b} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies \sf{\boxed{\bold{b = -3}} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$