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Ivahew [28]
4 years ago
13

Help!!! (15 points!)Will mark brainliest!!! Simplify completely 10x^6y^3+20x^3y^2 over 5x^3y

Mathematics
1 answer:
Lyrx [107]4 years ago
8 0

The answer completely simplified would be:

{2y}^{2} {x}^{3}  + 4y

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What is the rate of change of y=-4/9x+5
WARRIOR [948]

Answer:

Rate of change of y is -  \frac{4}{9}

Step-by-step explanation:

y =  -  \frac{4}{9} x + 5 \\  \\ differentiating \: with \: respect \: to \: x \\  \\  \frac{dy}{dx}  =  -  \frac{4}{9} \frac{d}{dx} x +  \frac{d}{dx} 5 \\  \\  \frac{dy}{dx}  =  -  \frac{4}{9} .1 +  0 \\  \\  \huge \red{\frac{dy}{dx}  =  -  \frac{4}{9} } \\  \\ rate \: of \: change \: of \: y =-  \frac{4}{9}

8 0
3 years ago
Solve this system of equations by any method.<br> 5x + y = -13<br> 4x + 3y= -17
irga5000 [103]
5x + y = -13.....multiply by -3
4x + 3y = -17
-----------------
-15x - 3y = 39 (result of multiplying by -3)
4x + 3y = -17
-----------------add
-11x = 22
x = -22/11
x = -2

5x + y = -13
5(-2) + y = -13
-10 + y = -13
y = -13 + 10
y = -3

solution (-2,-3)
5 0
4 years ago
The average monthly cell phone bill was reported to be $50.07 by the U.S. Wireless Industry. Random Sampling of a large cell pho
zalisa [80]

Answer:

The null and alternative hypotheses are:

H_{0}:\mu= 50.07

H_{a}:\mu>50.07

Under the null hypothesis, the test statistic is:

t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}} }

Where:

\bar{x} = 52.86 is the sample mean

s=7.0132 is the sample standard deviation

n=10 is the sample size

\therefore t=\frac{52.86-50.07}{\frac{7.0132}{\sqrt{10}} }    

          =1.26

Now, the right tailed t critical value at 0.05 significance level for df = n-1 = 10-1 = 9 is:

t_{critical}=1.833

Since the t statistic is less than the t critical value at 0.05 significance level, therefore,we fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the average phone bill has increased.


4 0
3 years ago
A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam. Find
natta225 [31]

The tension in the cable is given by the newton's first law will be 163.622 N.

<h3>What is newton's first law?</h3>

The summation of the force is equal to zero.

The formula is given as

ΣF = 0

Where m is the mass of the body and a is the acceleration.

A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam.

Then the tension in the cable will be

Let T be the tension in the cable.

T sin 29° + T sin 53° – 210 = 0

On simplifying, we have

T (sin 29° + sin 53°) = 210

                             T = 163.622 N

More about the newton's first law link is given below.

brainly.com/question/974124

#SPJ1

6 0
3 years ago
Drag and drop the correct numbers into the boxes to show the initial value and the range for each of the linear functions f(x) a
tatuchka [14]
I think  the answer is the 4th one
6 0
4 years ago
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