The answer you are looking for is .1
Answer:
y = -2x + 7
Step-by-step explanation:
tbh too lazy to explain
Answer: 8 hours
Step-by-step explanation:
Let x be the time before they meet ( in hours)
Speed of Sam = 12 mph
Sped of Fred = 9 mph
Distance = Speed × time
Distance covered by Sam in x hours = 12x
Distance covered by Fred in x hours = 9x
<em> (Distance) (rate1) (time1) (rate2) (time2)</em>
Total distance between them: 168 = 12 x + 9 x
![\Rightarrow\ 168= 21x\\\\\Rightarrow\ x=\dfrac{168}{21}=8](https://tex.z-dn.net/?f=%5CRightarrow%5C%20168%3D%2021x%5C%5C%5C%5C%5CRightarrow%5C%20x%3D%5Cdfrac%7B168%7D%7B21%7D%3D8)
Hence, the number of hours before they meet if Sam runs 12 mph and Fred runs 9 mph. = 8
Answer:
42 divided by 2
Step-by-step explanation:
That will give you 21.
DR/dt= -5inM-¹
dH/dt = 5inM-¹
recall V=πr²h
dV/dr = 2πrh
dV/dh= πr²
dV/dt = ½{ (dH/dt • dV/dH) + (dV/dr • dr/dt)}
dV/dt = ½{ ( 5×πr²) + (2πrh×-5)}
dV/dt = ½{ 5πr² -10πrh}
= ½{ 80π - 120π}
= -20π inM-¹