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dedylja [7]
4 years ago
10

At Deb’s Deli, a customer may choose either a sandwich and a salad or a sandwich and a soup for the lunch special. There are 5 c

hoices of sandwich, 4 choices of salad, and 3 choices of soup. How many possible lunch special combinations can be ordered?
Mathematics
1 answer:
Tju [1.3M]4 years ago
3 0

Answer: 35

Step-by-step explanation:

Given : At Deb’s Deli, a customer may choose either a sandwich and a salad or a sandwich and a soup for the lunch special.

The number of choices for sandwiches = 5

The number of choices for salad = 4

The number of choices for soup = 3

Now, the number of  possible lunch special combinations can be ordered will be :-

5\times4+5\times3=20+15=35

Hence, the number of  possible lunch special combinations can be ordered will be 35.

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-18 - 3 /4 v = 3<br> I need help with this who is smart enough to solve it
Blababa [14]

Answer:

v =-28

Step-by-step explanation:

-18 - 3 /4 v = 3

Add 18 to each side

-18+18 - 3 /4 v = 3+18

-3/4 v = 21

Multiply each side by -4/3 to isolate v

-4/3 *-3/4v = 21*-4/3

v =-28

8 0
3 years ago
Read 2 more answers
Plz help I'll appreciate it
Nutka1998 [239]
The unit rate is 6 I think
5 0
3 years ago
Penelope determined the solutions of the quadratic function by completing the square. F(x) = 4x2 8x 1 –1 = 4x2 8x –1 = 4(x2 2x)
Ymorist [56]

By solving the quadratic equation using completing the square method we got that Penelope should have added 4 to both sides instead of adding 1.

<h3>What is quadratic equation ?</h3>

Any equation of the form ax^2+bx+c=0 where x is variable and a, b, and c are any real numbers where a ≠ 0 is called quadratic equation .

Given work of Penelope is

$$\begin{aligned}&f(x)=4 x^{2}+8 x+1 \\&-1=4 x^{2}+8 x \\&-1=4\left(x^{2}+2 x\right) \\&-1+1=4\left(x^{2}+2 x+1\right) \\&0=4(x+2)^{2} \\&0=(x+2)^{2} \\&0=x+2 \\&-2=x\end{aligned}$$

Now we can see that Penelope determined the solutions of the quadratic function by completing the square. so he must have been done as following

$$\begin{aligned}&f(x)=4 x^{2}+8 x+1 \\&-1=4 x^{2}+8 x \\&-1=4\left(x^{2}+2 x\right) \\&-1+4=4\left(x^{2}+2 x+1\right) \\&3=4(x+2)^{2} \\&\frac{3}{4} =x+2)^{2} \\&\frac{\pm\sqrt3}{2} =x+2 \\&\frac{-2\pm\sqrt3}{2} =x\end{aligned}$$

By solving the quadratic equation using completing the square method we got that Penelope should have added 4 to both sides instead of adding 1.

To learn more about quadratic equations visit : brainly.com/question/1214333

8 0
2 years ago
If you flipped the graph of y = x2 + 2x - 2 vertically, you would get the graph of y = -(x2 + 2x - 2). true or false
lyudmila [28]
Hi friend,
If you flipped the graph y=x^2+2x-2 vertically, you would get the graph y=-(x^2+2x-2) TRUE. 
Hope this helps you!
7 0
4 years ago
Read 2 more answers
PLZZZZ help as soon as possible
sammy [17]

Answer:

JK = 11

Step-by-step explanation:

JK ≅ JM

where

JK = 3x - 16

JM = 2x - 7

3x - 16 = 2x - 7

group like terms

3x - 2x = 16 - 7

x = 9

<u>plugin x=9 into JK</u>

JK = 3x - 16

JK = 3(9) - 16

JK = 11

6 0
3 years ago
Read 2 more answers
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