Ask question

Ask question

All categories

3 years ago

14

Help please!!! Anything would be appreciated :3

1 answer:

Alex17521 [72]3 years ago

4 0

Assuming it’s a regular polygon :225

You might be interested in

A 10 inch cookie cake is divided into 8 slices. What is the area of 3 slices

brilliants [131]

Answer:

The area of 3 slices is $\frac{75}{8}\pi\ in^2$ or approximate $29.4\ in^2$

Step-by-step explanation:

<em>Find out the area of the cookie cake</em>

The area of the circle (cookie cake) is

$A=\pi r^{2}$

we have

$r=10/2=5\ in$ ----> the radius is half the diameter

substitute

$A=\pi (5)^{2}$

$A=25\pi\ in^{2}$

Remember that the area of the complete cookie cake subtends a central angle of 360 degrees

If the cake is divided into 8 slices

then

The central angle of each slice is equal to

360/8=45°

The central angle of 3 slices is equal to

3(45°)=135°

By proportion

Find out the area of 3 slices

Let

x ----> the area of 3 slices

$\frac{25\pi}{360}=\frac{x}{135}\\\\x=25\pi(135)/360\\\\x=\frac{3,375}{360}\pi\ in^2$

Simplify

$\frac{75}{8}\pi\ in^2$ ----> exact value of the area of 3 slices

Find out the approximate value of the area of 3 slices

assume

$\pi =3.14$

substitute

$\frac{75}{8}(3.14)=29.4\ in^2$

5 0

4 years ago

If 17y-24y+13y=210+y, what is the value of y?

Debora [2.8K]

$17y - 24y + 13y = 6y$
$6y - y = 5y$
$5y = 210$
$\frac{210}{5}$

210/5 =42

6 0

3 years ago

A piece of wire of length 5050 is cut, and the resulting two pieces are formed to make a circle and a square. Where should the

algol [13]

Answer:

x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.

Step-by-step explanation:

Let x be the length of wire that is cut to form a circle within the 5050 wire, so 5050 - x would be the length to form a square.

A circle with perimeter of x would have a radius of x/(2π), and its area would be

$A_c = \pir^2 = \pi (\frac{x}{2pi})^2 = \frac{x^2}{4\pi}$

A square with perimeter of 5050 - x would have side length of (5050 - x)/4, and its area would be

$A_s = (\frac{5050 - x}{4})^2 = \frac{(5050 - x)^2}{16}$

The total combined area of the square and circles is

$\sum A = A_c + A_s = \frac{x^2}{4\pi} + \frac{(5050 - x)^2}{16}$

To find the maximum and minimum of this, we just take the 1st derivative, and set it to 0

$A' = \frac{2x}{4\pi} + \frac{-2(5050-x)}{16} = 0$

$\frac{x}{2\pi} - \frac{5050 - x}{8} = 0$

Multiple both sides by 8π and we have

$4x - 5050\pi + x\pi = 0$

$x(4 + \pi) = 5050\pi$

$x = \frac{5050\pi}{4 + \pi} = 2221.5$

At x = 2221.5:

$A = \frac{x^2}{4\pi} + \frac{(5050 - x)^2}{16}$ = 392720 + 500026 = 892746 [/tex]

At x = 0, $A = 5050^2/16 = 1593906$

At x = 5050, $A = \frac{5050^2}{4\pi} = 2029424$

As 892746 < 1593906 < 2029424, x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.

3 0

3 years ago

HELP PLZZZZZZ!!!!!!!!<br> F=fg/f+g-d<br> solve for f<br> F does not equal f<br> SHOW YOUR WORK

Flura [38]

Is this even a problem

3 0

3 years ago

Anyone know what (-4) x (-6) x (-3) x (-5) is? (Multiplication) I’m unsure of my answer

FromTheMoon [43]

360. i just used a calculator lol

4 0

3 years ago