Ask question

Ask question

All categories

Tcecarenko [31]

3 years ago

7

Chet is a salesman whose base pay plus commissions amounted to $48,560 last year. If his base pay was $22,380 and he made $74,80

0 in sales last year, what was his rate of commission? A. 65% B. 35% C. 30% D. 46%

2 answers:

Nataliya [291]3 years ago

6 0

For APEX your answer would be 35%

ICE Princess25 [194]3 years ago

4 0

Answer:

B. 35%

Step-by-step explanation:

We have been given that Chet is a salesman whose base pay plus commissions amounted to $48,560 last year. His base pay was $22,380 and he made $74,800 in sales last year.

First of all, we will find amount of commission by subtracting base pay from total salary.

$\text{Amount of commission}=\$48,560-\$22,380$

$\text{Amount of commission}=\$26,180$

Since Chet sold $74,800 worth items, so we need to find $26,180 is what percent of $74,800.

$\text{Rate of commission}=\frac{\$26,180}{\$74,800}\times 100$

$\text{Rate of commission}=0.35\times 100$

$\text{Rate of commission}=35\%$

Therefore, option B is the correct choice.

You might be interested in

How much will it cost to fill up an empty 12-gallon take if gasoline costs $1.1599 per gallon

aliina [53]

Answer:

13.9188 dollars

Step-by-step explanation:

1.1599 * 12 = 13.9188

8 0

3 years ago

Read 2 more answers

A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let $S(t)$ be the amount of sugar in the tank at time $t$ . Then $S(0)=25$ .

Sugar is added to the tank at a rate of <em>P</em> lb/min, and removed at a rate of

$\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}$

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

$\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}$

Separate variables, integrate, and solve for <em>S</em>.

$\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt$

$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

$-100\ln\left|P-\dfrac S{100}\right|=t+C$

$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

$\dfrac S{100}=P-Ce^{-100t}$

$S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}$

Use the initial value to solve for <em>C</em> :

$S(0)=25\implies 25=100P-C\implies C=100P-25$

$\implies S(t)=100P-(100P-25)e^{-100t}$

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

$1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}$

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick <em>P</em> such that

$S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}$

5 0

3 years ago

Does anyone know the correct choice for this question? If its correct ill mark you as the best answer choice! Please!

victus00 [196]

Answer:

H

Step-by-step explanation:

Once graphed, the line passes through (-4,2) while the others do not

7 0

3 years ago

9multiply root 3 by 3 root 5

ludmilkaskok [199]

Answer:

$\frac{9 \sqrt{3} }{3 \sqrt{5} } \\ = \frac{3 \sqrt{3} }{ \sqrt{5} }$

Hope it helps!

7 0

3 years ago

A hotel room cost $79 per night. Meg's family is getting 2 rooms for 5 nights for their trip.

SCORPION-xisa [38]

$790 because it would be 79 times 10

6 0

2 years ago