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2 years ago

HELP ASAP!!!!!!What is the equation of a circle with center (1, -4) and radius 2?

Mathematics

1 answer:

sertanlavr [38]2 years ago

8 0

Answer:

(x)^2+ (y+2)^2 = 49

Step-by-step explanation:

The standard form of a circle is

(x-h)^2+ (y-k)^2 = r^2 where (h,k) is the center and r is the radius

(x-0)^2+ (y--2)^2 = 7^2

(x)^2+ (y+2)^2 = 49

this is just a example

lmk if u get it

Step-by-step explanation:

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30 POINTS!!!!!!!! JoeNah, DeKobian and Evan wrote equations to calculate the amount of money in a savings account after one year

castortr0y [4]

Answer:

See the explanation for the answer to this question

Step-by-step explanation:

Let

B ---> the balance of money saved.

M ---> the amount invested in dollars

JoeNah's Equation

M=$100

$B=1.5(100)=\$150$

Dekobian's Equation

M=$100

$B=100+0.05(100)=\$105$

Evan's Equation

M=$100

$B=M(1+0.05)$

Substitute

$B=100(1+0.05)=\$105$

Dekobian's equation and Evan's equation are correct! :)

JoeNah's equation is wrong. :(

Hope this helps you!

Have a good evening!

4 0

2 years ago

PLEASE HELP!!! <br>Please and thank you

Helga [31]

Hello.

17. ( 3 + 5 ) · 8 = 64

18. 4 · ( 6 - 2 ) + 7 = 23

19. 10 ÷ ( 3 + 2 ) · 4 = 8

20. ( 3 + 6 ) · 2 = 18

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5 0

3 years ago

Find the median,mode, and range for each set of number

4vir4ik [10]

5, 5, 9, 12, 18, 22, 25 put numbers in order least to greatest
25 -5 = 20 that is the range
12 is the middle number this is the median
5 is the mode, it is the number that is repeated the most

7 0

2 years ago

Read 2 more answers

The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep

Alchen [17]

Ooh, fun

geometric sequences can be represented as
$a_n=a(r)^{n-1}$
so the first 3 terms are
$a_1=a$
$a_2=a(r)$
$a_2=a(r)^2$

the sum is -7/10
$\frac{-7}{10}=a+ar+ar^2$
and their product is -1/125
$\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3$

from the 2nd equation we can take the cube root of both sides to get
$\frac{-1}{5}=ar$
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
$\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r$
subsituting -1/5 for ar
$\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r$
which simplifies to
$\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}$
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for $ax^2+bx+c=0$
$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$
so
for 2r²-5r+2=0
a=2
b=-5
c=2

$r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}$
$r=\frac{5 \pm \sqrt{25-16}}{4}$
$r=\frac{5 \pm \sqrt{9}}{4}$
$r=\frac{5 \pm 3}{4}$
so
$r=\frac{5+3}{4}=\frac{8}{4}=2$ or $r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}$

use them to solve for the value of a
$\frac{-1}{5}=ar$
$\frac{-1}{5r}=a$
try for r=2 and 1/2
$a=\frac{-1}{10}$ or $a=\frac{-2}{5}$

test each
for a=-1/10 and r=2
a+ar+ar²= $\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}$
it works

for a=-2/5 and r=1/2
a+ar+ar²= $\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}$
it works

both have the same terms but one is simplified

the 3 numbers are $\frac{-2}{5}$ , $\frac{-1}{5}$ , and $\frac{-1}{10}$

6 0

3 years ago

Helllpppppp pleaseee<br> i will mark you brillllllll

frez [133]

Answer:

the answer of the question is k = 176

6 0

2 years ago

Read 2 more answers