All categories

3 years ago

HELP ASAP!!!!!!What is the equation of a circle with center (1, -4) and radius 2?

Mathematics

1 answer:

sertanlavr [38]3 years ago

8 0

Answer:

(x)^2+ (y+2)^2 = 49

Step-by-step explanation:

The standard form of a circle is

(x-h)^2+ (y-k)^2 = r^2 where (h,k) is the center and r is the radius

(x-0)^2+ (y--2)^2 = 7^2

(x)^2+ (y+2)^2 = 49

this is just a example

lmk if u get it

Step-by-step explanation:

You might be interested in

Arătati ca: (5 puterea n +5 puterea n+1 +5 la puterea n) se divide cu 31.

katen-ka-za [31]

I am taking french but im only 7% fluent as of yet

8 0

3 years ago

Plz tell me this solution it's very urgent

a_sh-v [17]

Step-by-step explanation:

here is fig 15

x=36 (v.o.a are equal)

36+y=180

y=180-36=144

y=z=144 vertically

3 0

3 years ago

A and B someone can help ny plis

kolezko [41]

Answer:

Part A: 15 and 100 are the coefficients!

Part B: Two terms in the expression!

Step-by-step explanation:

3 0

3 years ago

Find the value of the expression. 7! ÷ 3! 5,040 5,034 840 24

koban [17]

First, let's review what the "factorial operator" ! means.

5! = 5*4*3*2*1.

3! = 3*2*1

7! = 7*6*5*4*3*2*1

Then:

7! 7*6*5*4*3*2*1 7*6*5*4 5040
----- = ----------------------- = ------------- = ----------- = 5040 (answer)
3! 3*2*1 1 1

3 0

3 years ago

A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. (a) What must be true

valentina_108 [34]

Answer:

(a) The distribution of the sample mean ( $\bar x$ ) is N (68, 4.74²).

(b) The value of $P(\bar X$ is 0.7642.

Step-by-step explanation:

A random sample of size n = 10 is selected from a population.

Let the population be made up of the random variable X.

The mean and standard deviation of X are:

$\mu=68\\\sigma=15$

(a)

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. n = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

$\mu_{\bar x}=\mu=68$