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pashok25 [27]
2 years ago
11

HELP ASAP!!!!!!What is the equation of a circle with center (1, -4) and radius 2?

Mathematics
1 answer:
sertanlavr [38]2 years ago
8 0

Answer:

(x)^2+ (y+2)^2 = 49

Step-by-step explanation:

The standard form of a circle is

(x-h)^2+ (y-k)^2 = r^2 where (h,k) is the center and r is the radius

(x-0)^2+ (y--2)^2 = 7^2

(x)^2+ (y+2)^2 = 49

this is just a example

lmk if u get it

Step-by-step explanation:

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The Fundamental Theorem of Calculus regarding geometry states that 
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Where F is the indefinite integral of g(x)

The first step is to integrate g(x)
\int\ {4x} \, dx = \frac{4x^{1+1} }{1+1} = \frac{4x^{2} }{2} =2 x^{2}

Then substitute the value of b and a=1 into 2x^{2}

[2 (b)^{2}]-[2 (1)^{2}] = 240
2b^{2} -2=240
2b^{2}=240+2
2b^{2}=242
b^{2}= \frac{242}{2}
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Hence the limit of the area under g(x) is between a=1 and b=11

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