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m_a_m_a [10]
3 years ago
6

Pls answer with working out pls. thnx

Mathematics
1 answer:
siniylev [52]3 years ago
8 0
3) mean = (5×o+9×1+7×2+4×3+3×4+2×5)/30
= (0+9+14+12+12+10)/30
= 57/30 = 1.9

4)same way,mean = 76/32 = 2.38
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Step-by-step explanation:

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Say 135,791,357.91 in words
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One hundred and thirty five million, 7 hundred and ninety one thousand and three hundred and fifty seven point nine one
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For which value of x is the equation 3(3 + x) = 15 + x true?<br> A) 1 <br> B) 2 <br> C) 3 <br> D) 4
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C

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3(3 + x) = 15 + x

Open bracket

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Collecting like terms

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In a random sample of students who took the SAT test, 427 had paid for coaching courses and the remaining 2733 had not. Calculat
Dvinal [7]

Answer:

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

427 had paid for coaching courses and the remaining 2733 had not.

This means that n = 427 + 2733 = 3160, \pi = \frac{427}{3160} = 0.1351

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The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 - 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.1232

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 + 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.147

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

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