To measure George's rate of change, we first set out two pairs of independent and dependent data which in this case is the day number and the point

Independent Data: Day 2 Independent Data: Day 4
Dependent Data: 8 points Dependant Data: 12 points

Then we find the difference between the two independent values and the two dependent values

4 - 2 = 2
12 - 8 =4

To find the rate we use the following formula
the difference of dependent value ÷ the difference of independent value =
4 ÷ 2 = 2

Hence the average rate of change is an increase of 2 points a day

6 0

3 years ago

Use the difference of squares identity to write this polynomial expression in factored form: 9x2 − 49.

qwelly [4]

9x^2-49
It equals:
(3x+7)(3x−7)
Hope this helps!

7 0

4 years ago

Read 2 more answers

Find all of the points of the form (x −1) which are 4 unit from the point (3,2)

Bond [772]

Answer:

$(3+2\sqrt{2},2+2\sqrt{2}),(3-2\sqrt{2},2-2\sqrt{2})$

Step-by-step explanation:

$Points\ are\ of\ the\ form\ (x,x-1)\\\\Distance\ of\ these\ points\ from\ (3,2)=4\\\\\sqrt{(x-3)^2+(x-3)^2}=4\\\\\sqrt{(x-3)^2+(x-1-2)^2}=4\\\\\sqrt{2(x-3)^2}=4\\\\2(x-3)^2=16\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ square\ both\ the\ sides\\\\(x-3)^2=\frac{16}{2}\\\\(x-3)^2=8\\\\(x-3)=\pm 2\sqrt{2}\ \ \ \ \ \ \ \ \ \ \ square\ root\ both\ the\ sides\\\\x=3\pm 2\sqrt{2}\\\\When\ x=3+2\sqrt{2}\ \ \Rightarrow x-1=3+2\sqrt{2}-1=2+2\sqrt{2}\\\\When\ x=3-2\sqrt{2}\ \ \Rightarrow x-1=3-2\sqrt{2}-1=2-2\sqrt{2}$

4 0

3 years ago