Question

A line passes through the point (4, –6) and has a slope of -3/4. Which is the equation of the line?

Answer 1

$\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{-6})~\hspace{10em} slope = m\implies -\cfrac{3}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-6)=-\cfrac{3}{4}(x-4) \\\\\\ y+6=-\cfrac{3}{4}x+3\implies y=-\cfrac{3}{4}x-3$