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dimaraw [331]
2 years ago
7

The diameter of circle p below is 39.4 what is the approximate area of circle p???

Mathematics
1 answer:
givi [52]2 years ago
7 0

1134.11

This should be the answer

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Can anyone help me I don’t understand plz
Citrus2011 [14]

There we have an information of two functions g(t)\,  and \, h(t)

Using this two functions g(t)\,  and \, h(t), we need to find the composition of functions (h\circ g)(t).

The composition of two functions h and g is the new function , by performing g first and then performing h.

(h\circ g)(t)=h(g(t))

g(t)=3(t+1)

h(t)=2t

Composition of h and g (t) = (h\circ g)(t)

=h(g(t))

First plugin the value of g(t)=3(t+1)

h(g(t))=h(3(t+1))

=h(3t+3)

We know that h(t)=2t, we need to find h(3t+3),

That is, to replace t by 3t+3,

=2(3t+3)

Now distribute 2 into 3t+3,

=6t+6

Now plug in t=-6,

h(g(-6))=6(-6)+6

=-36+6 \\ =-30

Thus the solution is (D). h(g(-6))=-30.

5 0
3 years ago
Read 2 more answers
Hey, can someone plz help me.
PSYCHO15rus [73]

Answer:

3, -1

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
It is thought that not as many Americans buy presents to celebrate Valentine's Day anymore. A random sample of 40 Americans yiel
evablogger [386]

Answer:

98% confidence interval of the true proportion of all Americans who celebrate Valentine's Day

 (0.3672 , 0.7328)

Step-by-step explanation:

<u><em>Explanation:</em></u>-

Given Random sample size n =40

Sample proportion

                            p = \frac{x}{n} = \frac{22}{40} = 0.55

98% confidence interval of the true proportion of all Americans who celebrate Valentine's Day

   

          (p-Z_{\alpha } \sqrt{\frac{pq}{n} } , p + Z_{\alpha } \sqrt{\frac{pq}{n} } )

         

The Z-value Z₀.₉₈ = Z₀.₀₂ = 2.326

98% confidence interval of the true proportion of all Americans who celebrate Valentine's Day

    (0.55-2.326\sqrt{\frac{0.55 X0.45}{40} } , 0.55 + 2.326\sqrt{\frac{0.55 X0.45}{40} } )

  ( 0.55 - 0.1828 , 0.55 + 0.1828)

  (0.3672 , 0.7328)

         

6 0
3 years ago
Read 2 more answers
2) 1 - 3p+2p - 9<br> Your<br> answer<br> This is a required question
Pavlova-9 [17]

Answer:

-p - 8

Step-by-step explanation:

1 - 3p + 2p - 9 = -p - 8

7 0
3 years ago
SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council
fgiga [73]

Answer:

0.91517

Step-by-step explanation:

Given that SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council awards a certificate of excellence to all students who score at least 1350 on the SAT, and suppose we pick one of the recognized students at random.

Let A - the event passing in SAT with atleast 1500

B - getting award i.e getting atleast 1350

Required probability = P(B/A)

= P(X>1500)/P(X>1350)

X is N (1100, 200)

Corresponding Z score = \frac{x-1100}{200}

P(X>1500)/P(X>1350)\\= \frac{P(Z>2)}{P(Z>1.25} \\=\frac{0.89435}{0.97725} \\=0.91517

4 0
3 years ago
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