A) We want to know when h=10 so
10=-16t^2+40t+3
16t^2-40t+7=0
Using the quadratic formula:
t=(40±√1152)/32
t≈0.189 and 2.311 seconds
So it is at 10 ft twice, about 2/10 of a second when it is rising and at 2 3/10 of a second when it is falling...
b.
The maximum height of the ball is when velocity is equal to zero, or dh/dt=0
dh/dt=-32t+40, dh/dt=0 when 32t=40, t=40/32=5/4=1.25 seconds
h(1.25)=28ft
So the maximum height of the ball occurs after 1.25 seconds and reaches a height of 28 feet.
The answer to 52\8 is 6.5.
Answer:
meeeeeeeeeeee
Step-by-step explanation:
Answer:
1) ¼
2) yes
Step-by-step explanation:
1) P(A) = 13/52 = 1/4
P(B) = 4/52 = 1/13
P(A^B) = 1/52
P(A|B) = (1/52) ÷ (1/13) = 1/4
Since P(A|B) = P(A), they are independent
The Scale is 1/4. 1800/4= 450 and 1200/4= 300
